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emmainna [20.7K]
3 years ago
15

To evaluate 43/2 find A) the square of 4 and then take the cube root. B) the cube of 4 and then take the square root. C) the squ

are root of 2 times the cube root of 4. Eliminate D) the cube root of 4 and then take the square root.
Mathematics
1 answer:
tatiyna3 years ago
4 0

Answer:

  B) the cube of 4 and then take the square root

Step-by-step explanation:

43/2 = 21.5

___

The answer choices suggest you want ...

  4^(3/2) . . . . . . . appropriate math symbols are very helpful

This can be evaluated several ways:

  4^{\frac{3}{2}}=\sqrt{4^3}=(\sqrt{4})^3=10^{\frac{3}{2}\log{4}}\\\\=8

_____

Since the 3 is in the numerator of the fraction, it represents a cube, not a cube root. Any of the answer choices suggesting cube root is involved are incorrect. (Eliminating those leaves only the correct answer choice.)

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Read 2 more answers
Find cube root of 175616 ??​
Tpy6a [65]

Answer:

56

Step-by-step explanation:

Cube root of 175616 by prime factorization method is 56

Solution:

To find cube root of 175616 by prime factorization method

A number that must be multiplied by itself three times to equal a given number is called cube root

Prime factorization method:

Prime factorization is a number written as the product of all its prime factors.

In order of finding cube root by prime factorization we use the following steps:

Step I : Obtain the given number

Step II : Resolve it into prime factors.

Step III : Group the factors in 3 in such a way that each number of the group is same

Step IV : Take one factor from each group

Step V : Find the product of the factors obtained in step IV. This product is the required cube root

Prime factorization of 175616:

\text{ prime factors of 175616 } = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 7 \times 7 prime factors of 175616 =2×2×2×2×2×2×2×2×2×7×7×7

Thus we get,

\sqrt[3]{175616} = \sqrt[3]{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 7 \times 7}

3

175616

=

3

2×2×2×2×2×2×2×2×2×7×7×7

Make the groups of 3 of equal numbers

\sqrt[3]{175616} = \sqrt[3]{2 \times 2 \times 2} \times \sqrt[3]{2 \times 2 \times 2 \times } \times \sqrt[3]{2 \times 2 \times 2} \times \sqrt[3]{7 \times 7 \times 7}

3

175616

=

3

2×2×2

×

3

2×2×2×

×

3

2×2×2

×

3

7×7×7

So there are 4 equal groups. So from that group take one factor out

\sqrt[3]{175616} = 2 \times 2 \times 2 \times 7 = 56

3

175616

=2×2×2×7=56

Thus Cube root of 175616 by prime factorization method is 56

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