This is the same as its freezing point
hope this helps
Answer:
561 g P₂O₃
Explanation:
To find the mass of P₂O₃, you need to (1) convert moles H₃PO₃ to moles P₂O₃ (via mole-to-mole ratio from equation coefficients) and then (2) convert moles P₂O₃ to grams P₂O₃ (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the amount of sig figs in the given value.
Atomic Mass (P): 30.974 g/mol
Atomic Mass (O): 15.998 g/mol
Molar Mass (P₂O₃): 2(30.974 g/mol) + 3(15.998 g/mol)
Molar Mass (P₂O₃): 109.942 g/mol
1 P₂O₃ + 3 H₂O -----> 2 H₃PO₃
10.2 moles H₃PO₃ 1 mole P₂O₃ 109.942 g
---------------------------- x -------------------------- x ------------------- = 561 g P₂O₃
2 moles H₃PO₃ 1 mole
Answer:
Δ
N = -1
Explanation:
Step 1: Data given
2 SO2(g) + O2(g) ⇌ 2 SO3(g)
For 2 moles of SO2 we need 1 mol of O2 to produce 2 moles of SO3
Step 2: Calculate Δ
Δ
N wNill be the sum of moles of products minus the sum of moles of reactants.
Number of moles of products = number of moles of SO3 = 2
Number of moles of reactants = number of moles of SO2 + number of moles of O2 = 2 + 1 = 3
Δ
N = 2 - 3 = -1
Answer:
A chemical formula is an expression that shows the elements in a compound and the relative proportions of those elements.
Explanation:
If only one atom of a specific type is present, no subscript is used. For atoms that have two or more of a specific type of atom present, a subscript is written after the symbol for that atom
Answer:
(2) The lowest energy orbits are those closest to the nucleus.
Explanation:
In the Bohr theory the electrons describe circular orbits around the nucleus of the atom without radiating energy, therefore to maintain the circular orbit, the force that the electron experiences, that is, the coulombian force due to the presence of the nucleus, must be equal to the centripetal force.
The electron only emits or absorbs energy in the jumps from one allowed orbit to another, with only one jump occurring at a time, from layer K (n = 1) to layer L (n = 2), without going through intermediate orbits. In said change it emits or absorbs a photon whose energy is the difference in energy between both levels.
In Bohr's model, it is stipulated that the energy of the electron is greater the greater the radius r, so the lowest energy orbits are those closest to the nucleus.
