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3 years ago

Please help me out with this.......

Mathematics

1 answer:

ehidna [41]3 years ago

6 0

Answer:

y = 0.5x + 5

Step-by-step explanation:

The equation is in slope- intercept form

y = mx + c ( m is the slope and c the y- intercept )

Given the ordered pair (0, 5 ) then c = 5

Calculate the multiplier using the slope formula

with (x₁, y₁ ( = (0, 5) and (x₂, y₂ ) = (2, 6) ← 2 ordered pairs from the table

m = $\frac{6-5}{2-0}$ = 0.5, hence

y = 0.5x + 5 ← equation relating x and y

You might be interested in

A company manufactures cell phones. In August, a random sample of 125 cell phones was inspected, and 3 phones were found to be d

german

Answer:

192

Step-by-step explanation:

To find how many phones are expected to be defective, we need to represent the values in a fraction.

$\dfrac{x}{8000}=\dfrac{3}{125}$

x = number of defective phones

Now we can solve this using algebra.

To get the value of x we need to multiply both sides by 8000 to leave x alone.

$x=\dfrac{3}{125}(8000)$

$x=0.024(8000)$

$x=192$

So around 192 cell phones are expected to be defective out of 8000 phones.

6 0

3 years ago

Jason and Britton are driving to St. George. Jason got a 20 mile head start and drove an

harina [27]

Answer:

2 hours, 150 miles

Step-by-step explanation:

The relation between time, speed, and distance can be used to solve this problem. It can work well to consider just the distance between the drivers, and the speed at which that is changing.

<h3>Separation distance</h3>

Jason got a head start of 20 miles, so that is the initial separation between the two drivers.

<h3>Closure speed</h3>

Jason is driving 10 mph faster than Britton, so is closing the initial separation gap at that rate.

<h3>Closure time</h3>

The relevant relation is ...

time = distance/speed

Then the time it takes to reduce the separation distance to zero is ...

closure time = separation distance / closure speed = 20 mi / (10 mi/h)

closure time = 2 h

Britton will catch up to Jason after 2 hours. In that time, Britton will have driven (2 h)(75 mi/h) = 150 miles.

<em>Additional comment</em>

The attached graph shows the distance driven as a function of time from when Britton started. The distances will be equal after 2 hours, meaning the drivers are in the same place, 150 miles from their starting spot.