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3 years ago

How do I compare my fractions

Mathematics

2 answers:

melamori03 [73]3 years ago

8 0

So you are comparing 6/9 and 3/5. First, multiply the 6 from the first one and 5 from the second (numbers that cross each other). That would be 30. Then, the the same with the other numbers that cross which is 3 and 9. That would be 27. Think, which is greater? 30 or 27? Point the crocodile mouth < to the greater number that crosses. So 30 goes on the 6/9 side and 27 goes on the 3/5 side. Hope you understand! Sorry, I can tell you answer if you want :) <span />

Alexandra [31]3 years ago

7 0

First make both denominators the same. Then compare

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Multiplicative inverse<br> 1.the number 0 (for the real numbers

Kobotan [32]

Division is the inverse of the multiplication.

5 0

4 years ago

The length of a rectangle is 6 meters more than three times the width. The perimeter of the rectangle is 44 meters. What are the

Oksana_A [137]

Answer:

width=4

length=18

Step-by-step explanation:

length-6=3width

length=3width+6

also:

perimeter of the rectangle=2(length+width)

44/2=width+length

22=width+length

now put the length we found in the 1st equation, in 22=width+length

=>22=width+3width+6

22-6=4width

width=4

now do the exact same thing with one of these equations:

22=width+length

length=3width+6

I'd do it with the 1st one:

22=4+length

22-4= length

length=18

6 0

4 years ago

A closed box with a square base is to have a volume of 171 comma 500 cm cubed. The material for the top and bottom of the box co

Zepler [3.9K]

Answer:

$C(x)=\dfrac{20x^3+1715000}{x}\\$Minimum cost, C(35)=\$29,400$

The dimensions that will lead to minimum cost of the box are a base length of 35 cm and a height of 140 cm.

Step-by-step explanation:

Volume of the Square-Based box=171,500 cubic cm

Let the length of a side of the base=x cm

Volume $=x^2h$

$x^2h=171,500\\h=\dfrac{171500}{x^2}$

The material for the top and bottom of the box costs $10.00 per square centimeter.

Surface Area of the Top and Bottom $=2x^2$

Therefore, Cost of the Top and Bottom $=\$10X2x^2=20x^2$

The material for the sides costs $2.50 per square centimeter.

Surface Area of the Sides=4xh

Cost of the sides=$2.50 X 4xh =10xh

$\text{Substitute h}$=\dfrac{171500}{x^2} $into 10xh\\Cost of the sides=10x(\dfrac{171500}{x^2})=\dfrac{1715000}{x}$

Therefore, total Cost of the box

$= 20x^2+\dfrac{1715000}{x}\\C(x)=\dfrac{20x^3+1715000}{x}$

To find the minimum total cost, we solve for the critical points of C(x). This is obtained by equating its derivative to zero and solving for x.

$C'(x)=\dfrac{40x^3-1715000}{x^2}\\\dfrac{40x^3-1715000}{x^2}=0\\40x^3-1715000=0\\40x^3=1715000\\x^3=1715000\div 40\\x^3=42875\\x=\sqrt[3]{42875}=35$

Recall that:

$h=\dfrac{171500}{x^2}\\Therefore:\\h=\dfrac{171500}{35^2}=140cm$

The dimensions that will lead to minimum costs are base length of 35cm and height of 140cm.

Therefore, the minimum total cost, at x=35cm

$C(35)=\dfrac{20(35)^3+1715000}{35}=\$29,400$

8 0

3 years ago

Can someone check on this problem if I did it right this problem is about law of cosines just look at #1

lora16 [44]

Answer:

x = 5.57

Step-by-step explanation:

c² = a² + b² − 2ab cos C

x² = 10² + 6² − 2(10)(6) cos 29°

x = 5.57

Your answer and steps are correct.

8 0

4 years ago

11-8n=1-3n whats answer

musickatia [10]

Answer:

n=2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

11−8n=1−3n

11+−8n=1+−3n

−8n+11=−3n+1

Step 2: Add 3n to both sides.

−8n+11+3n=−3n+1+3n

−5n+11=1

Step 3: Subtract 11 from both sides.

−5n+11−11=1−11

−5n=−10

Step 4: Divide both sides by -5.

−5n

−5

−10

−5

n=2

6 0

4 years ago