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Lina20 [59]
3 years ago
10

Write an expression in factored form to represent the total area of each rectangle

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
7 0

The area of any rectangle is

           (the rectangle's length) times (the rectangle's width) .

If you have one or more specific rectangles to be discussed,
you'll have to reveal them.

natali 33 [55]3 years ago
4 0
L time W 
L= length
W=width so LxW
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Kenya exchanges $200 for euros (€). Suppose the conversion rate is €1 = $1.321. How many euros should Kenya receive?
Anon25 [30]
€151.40 would be the outcome i believe
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3 years ago
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Write the slope-intercept form of the equation of each line. identify the slopes y-intercept.
iren [92.7K]

Answer:

1. 3,0,y=3x

2. -3/5, 1, y=-3/5x+1

3. -2/3, -4,y=-2/3x-4

4. 0, 4, y=4

5. 1, 5, y=x+5

6. 2, 0, y=2x

7. 4, 5, y=4x+5

8. 3/2, 4, y=3/2x+4

hopefully this helps :)

5 0
3 years ago
Factor x^2 + 7x -18 Please help
Anton [14]
x^2 + 7x -18=\\
x^2-2x+9x-18=\\
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4 0
4 years ago
Keegan is priting and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total p
Damm [24]

Complete question is;

Keegan is printing and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total profits will be p(x) = -x³ + 4x² + x dollars, in thousands will be earned. How many t-shirts (rounded to the nearest whole number) should he print in order to make maximum profits? What will his profits rounded to the nearest whole dollar be if he prints that number of shirts?

Answer:

Number of t-shirts to make maximum profit = 2790 shirts

Maximum profit = $12,209

Step-by-step explanation:

From the question, we are given that the profit function is;

p(x) = -x³ + 4x² + x

For the maximum value of the profit function,

(dp/dx) = 0 and (d²p/dx²) < 0

Since, p(x) = -x³ + 4x² + x

Then,

(dp/dx) = -3x² + 8x + 1

at maximum point (dp/dx) = 0, thus;

-3x² + 8x + 1 = 0

Solving this using quadratic formula, the roots are;

x = -0.12 or 2.79

Also, (d²p/dx²) = -6x + 8

Now, let's put the roots of x into -6x + 8 and check for maximum value conditon;

at x = -0.12

(d²p/dx²) = -6(0.12) + 8 = 7.28 > 0

At x = 2.79

(d²p/dx²) = -6(2.79) + 8 = -8.74 < 0

Maximum has to be d²p/dx² < 0

So, the one that meets the condition is -8.74 < 0 at x = 2.79

Thus, the maximum of the profit function exists when the number of shirts, x = 2.79 (in thousands) = 2790

Now, the maximum profits that corresponds to this number of t-shirts of 2.79(in thousands) is obtained by putting 2.79 for x in the profit function;

So,

p(2.79) = -(2.79)³ + 4(2.79²) + 2.79

p(x) = -21.7176 + 31.1364 + 2.79

p(x) = 12.2088 (in thousand dollars) ≈ $12,209

6 0
3 years ago
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