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evablogger [386]
2 years ago
12

Anyone know the answer to the first one?

Mathematics
1 answer:
Debora [2.8K]2 years ago
4 0

Answer:

it's a multiple choice, really.

Step-by-step explanation:

take any prime number for Y and take a number that is a multiple of 3 for X.

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If 7 is added to the square of a positive integer, the result is 43. Find the positive integer
Blababa [14]

Answer:

6

Step-by-step explanation:

43-7=36

The square of 36 is 6.

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3 years ago
HELLPP ASAP PLS, FIRST PERSON TO ANSWER CORRECTLY GETS BRAINLIEST
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Step-by-step explanation:

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3 years ago
Languages Spoken in Australia
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2 years ago
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Eff traveled at an average speed of 65 miles per hour for 2.5 hours and then traveled at an average speed of 70 miles per hour f
AleksandrR [38]

Answer:

267.5 miles

Step-by-step explanation

65×2.5=162.5                

70×1.5=105

162.5+105=267.5

<h2>                                267.5</h2>
3 0
2 years ago
The time rate of change of a rabbit population PP is proportional to the square root of PP. At time t=0t=0 (months) the populati
frosja888 [35]

Answer:

\frac{dP}{\sqrt{P}} = k dt

And if we integrate both sides we got:

2 \sqrt{P} = kt +C

Where C is a constant., we can rewrite the expression like this:

\sqrt{P} = \frac{1}{2} (kt +C)

If we square both sides we got:

P = \frac{1}{4} (kt +C)^2

If we use the initial condition we have that:

P(0) = 100 = \frac{1}{4} (k*0 +C)^2

And we can solve for C like this:

400 = C^2

C = 20

And now we can find the derivate of the function and we got:

P'(t) = 2* \frac{1}{4} (kt + 20) * k

Using the condition P'(0) = 10 we got:

10 = \frac{1}{2} k (k*0 +20)

20 = 20 k

k= 1

And then the model is defined as:

P = \frac{1}{4} (t +20)^2

And for t =12 months we have:

P(12) = \frac{1}{4} (12 +20)^2 = 256

Step-by-step explanation:

For this case we cna use the proportional model given by:

\frac{dP}{dt} = k \sqrt{P}

Where k is a proportional constant, P the population and the represent the number of months

For this case we know the following initial condition P(0) =100 and P'(0) = 10

we can rewrite the differential equation like this:

\frac{dP}{\sqrt{P}} = k dt

And if we integrate both sides we got:

2 \sqrt{P} = kt +C

Where C is a constant., we can rewrite the expression like this:

\sqrt{P} = \frac{1}{2} (kt +C)

If we square both sides we got:

P = \frac{1}{4} (kt +C)^2

If we use the initial condition we have that:

P(0) = 100 = \frac{1}{4} (k*0 +C)^2

And we can solve for C like this:

400 = C^2

C = 20

And now we can find the derivate of the function and we got:

P'(t) = 2* \frac{1}{4} (kt + 20) * k

Using the condition P'(0) = 10 we got:

10 = \frac{1}{2} k (k*0 +20)

20 = 20 k

k= 1

And then the model is defined as:

P = \frac{1}{4} (t +20)^2

And for t =12 months we have:

P(12) = \frac{1}{4} (12 +20)^2 = 256

6 0
2 years ago
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