3x-7>2
add 7 to both sides: 3x>9
divide both sides by 3: x>9
the answer is 38.53 becauase it is...
The x-coordinate remains the same.
The y-coordinate was 5, above the x-axis, now it becomes -5, below the x-axis.
Answer: (3, -5)
Assuming P (usually written in upper case) represents a force normal to a given cross section.
If a point load is applied to any point of the section, stress concentration will cause axial stress to vary.
The context of the question considers the uniformity of axial stress at a certain distance away from the point of application (thus stress concentration can be neglected).
If a force P is applied through the centroid, sections will be stressed uniformly. However, if the force P is applied at a distance "e" from the centroid, the equivalent load on the section equals an axial force and a moment Pe. The latter causes bending of the member, causing non-uniform stress.
If we assume A=(uniform) cross sectional area, and I=moment of inertia of the section, then stress varies with the distance y from the centroid equal to
stress=sigma=P/A + My/I
where P=axial force, M=moment = Pe.
Therefore when e>0, the stress varies across the section.
