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3 years ago

A swimmer swims 110 m toward the shore in 72 s. What is the swimmers velocity in neters per second?

Physics

1 answer:

MrRissso [65]3 years ago

6 0

Answer:

1.53 m/s

Explanation:

Velocity is given in meters per second, so if it takes the swimmer 72 second to swim 110 meters:

m/s = 110 meters / 72 seconds = 1.527 or 1.53 m/s

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A well labelled diagram of outdoor thermometer

ElenaW [278]

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3 years ago

How would you find kinetic energy?

Flura [38]

Answer:

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v2. If the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

Explanation:

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2 years ago

Read 2 more answers

Two parallel square metal plates that are 1.5 cm and 22 cm on each side carry equal but opposite charges uniformly spread out ov

Mumz [18]

Answer:

The number of excess electrons are on the negative surface is $4.80\times10^{10}\ electrons$

Explanation:

Given that,

Distance =1.5 cm

Side = 22 cm

Electric field = 18000 N/C

We need to calculate the capacitance in the metal plates

Using formula of capacitance

$C=\dfrac{\epsilon_{0}A}{d}$

Put the value into the formula

$C=\dfrac{8.85\times10^{-12}\times(22\times10^{-2})^2}{1.5\times10^{-2}}$

$C=0.285\times10^{-10}\ F$

We need to calculate the potential

Using formula of potential

$V=Ed$

Put the value into the formula

$V=18000\times1.5\times10^{-2}\ V$

$V=270\ V$

We need to calculate the charge

Using formula of charge

$Q=CV$

Put the value into the formula

$Q=0.285\times10^{-10}\times270$

$Q=76.95\times10^{-10}\ C$

Here, the charge on both the positive and negative plates

$Q=+76.95\times10^{-10}\ C$

$Q=-76.95\times10^{-10}\ C$

We need to calculate the number of excess electrons are on the negative surface

Using formula of number of electrons

$n=\dfrac{q}{e}$

Put the value into the formula

$n=\dfrac{76.95\times10^{-10}}{1.6\times10^{-19}}$

$n=4.80\times10^{10}\ electrons$

Hence, The number of excess electrons are on the negative surface is $4.80\times10^{10}\ electrons$

8 0

3 years ago

what is the energy (in eV units) carried by one photon violet light that has a wavelength of 4.5e-7?

DaniilM [7]

The energy of a photon is given by
$E=hf$
where h is the Planck constant and f is the photon frequency.

We can find the photon's frequency by using the following relationship:
$f= \frac{c}{\lambda}$
where c is the speed of light and $\lambda$ is the photon's wavelength. By plugging numbers into the equation, we find
$f= \frac{c}{\lambda}= \frac{3 \cdot 10^8 m/s}{4.5 \cdot 10^{-7} m}=6.67 \cdot 10^{14}Hz$

And so now we can find the photon energy
$E=hf=(6.6 \cdot 10^{-34} Js)(6.67 \cdot 10^{14}Hz )=4.4 \cdot 10^{-19} J$

We know that 1 Joule corresponds to
$1 J = 1.6 \cdot 10^{-19} eV$
So we can convert the photon's energy into electronvolts:
$E= \frac{4.4 \cdot 10^{-19} J }{1.6 \cdot 10^{-19} J/eV}=2.75 eV$

4 0

4 years ago

A plane can fly 390 miles in the same time as it takes a car to go 120 miles. If the car travels 90 mph slower than the plane, f

never [62]

thats a hella slow plane

3 0

3 years ago