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harina [27]
3 years ago
7

The balanced equation for the combustion of Hydrogen is:

Chemistry
1 answer:
Semmy [17]3 years ago
4 0
B) 1.50 mol
Since O2 and H2O are in a 1:2 ratio, multiply 0.75×2 = 1.50
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Which of the following statements is true about what happens during a chemical reaction?
tiny-mole [99]

Answer: The correct option is A.

Explanation: In a chemical reaction, reactants react to form a number of products.

For the formation of products, the bonds of the individual reactants must be broken and the bonds of the products must be formed.

For example: Formation of water from hydrogen gas and oxygen gas. Reaction follows:

2H_2(g)+O_2(g)\rightarrow 2H_2O(l)

The Bonds of hydrogen and oxygen molecule are broken and new bonds between hydrogen and oxygen atoms are formed to give water molecule.

5 0
3 years ago
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Which of the following is true?
tresset_1 [31]

Answer:

B

Explanation:

The sun can be dangerous but it also helps our Earth in a lot of ways

4 0
3 years ago
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Use the information from the diagram to calculate the enthalpy of combustion for methane. (HELP ASAPPP!!)
Blizzard [7]

Answer:

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6 0
3 years ago
What volume, in milliliters, of a 0.997 M KOH solution is needed to neutralize 30.0 mL of 0.0400 M HCl?
deff fn [24]

Answer:

1.2 mL

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated:

HCl + KOH —> KCl + H₂O

From the balanced equation,

Mole ratio of the acid, HCl (nₐ) = 1

Mole ratio of base, KOH (n₆) = 1

Finally, we shall determine the volume of the base, KOH needed to neutralize the acid, HCl as follow:

Molarity of base, KOH (M₆) = 0.997 M

Volume of acid, HCl (Vₐ) = 30 mL

Molarity of acid, HCl (Mₐ) = 0.0400 M

Volume of base, KOH (V₆) =?

MₐVₐ / M₆V₆ = nₐ/n₆

0.04 × 30 / 0.997 × V₆ = 1/1

1.2 / 0.997 × V₆ = 1

Cross multiply

0.997 × V₆ = 1.2

Divide both side by 0.997

V₆ = 1.2 / 0.997

V₆ = 1.2 mL

Thus, the volume of the base, KOH needed to neutralize the acid is 1.2 mL.

7 0
3 years ago
25 points please help
maxonik [38]

Answer : Option (A) Accelerator 2 model has the lowest percentage of energy lost as waste.

Solution : Given,

For Accelerator 1 model,

Input energy = 2078.3 J

Wasted energy = 663.1 J

Output energy = 1415.2 J

For Accelerator 2 model,

Input energy = 7690.0 J

Wasted energy = 2337.5 J

Output energy = 5353.5 J

For Accelerator 3 model,

Input energy = 4061.9 J

Wasted energy = 2259.6 J

Output energy = 1802.3 J

Formula used for lowest percentage of energy lost as waste is:

% energy lost as waste = (Total energy wasted / Total input energy )  ×  100

For Accelerator 1 model,

% energy lost as waste = \frac{663.1}{2078.3}\times100 = 31.90%

For Accelerator 2 model,

% energy lost as waste = \frac{2337.5}{7690.0}\times100 = 30.39%

For Accelerator 3 model,

% energy lost as waste = \frac{2259.6}{4061.9}\times100 = 55.62%

So, we conclude that the Accelerator 2 model has the lowest percentage of energy lost as waste.



6 0
3 years ago
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