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kondor19780726 [428]
3 years ago
13

Which name is associated with a system of climate zones?

Chemistry
1 answer:
andrew11 [14]3 years ago
8 0

Answer: A. Wladimir Koppen.

I hope that this helps you and good luck!!

~Sara

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4. A balloon is filled with 3.0 L of helium at 310 K. The balloon is placed in an oven where the
77julia77 [94]

Answer:

3,29L

Explanation:

3.29L = V2

 

Formula: V1/T1 = V2/T2

--------------------

Given:

V1 = 3.0 L V2 = ?

T1 = 310 K T2 = 340 K

--------------------

Plugin:

(X stands in place of V2 just to make it easier to look at)

[3.0L / 310K = X / 340K]

(3.0L / 310K = 0.01L/K)

0.01L/K = X / 340K

(multiply 340K on both sides, it cancels out on the right)

0.01L/K * 340K = X

(0.01L/K * 340K = 3.29L)

**3.29L = X**

[or]

**3.29L = V2**

4 0
3 years ago
Question 11. Identify the reducing agent <br> Sn+2 + AG 0 —&gt; Sn0 + Ag+
Temka [501]

Answer:

Ag 0 is the reducing agent.

Explanation:

Reducing -> gaining electrons

Oxidizing -> losing electrons

Ag lost electrons (became more positive) since it went from a 0 charge to a +1 charge. Therefore it was oxidized. Ag+ is the oxidized product. Reactants that create an oxidized product are called reducing agents. This would make Ag 0 the reducing agent in this reaction.

4 0
2 years ago
Which shows the potential energy of particles in three substances, from least to greatest? liquid, solid, gas liquid, gas, solid
AleksandrR [38]

Answer:

Gas liquid solid

Explanation:

gases have a weak potential since they have a weak bond between molecules while in solids it's the strongest making them vibrate in a fixed position

3 0
3 years ago
A sample of sugar contains 1.505 × 1023 molecules of sugar. How many moles of sugar are present in the sample?
alisha [4.7K]
1 mole ------------ 6.02 x10²³ molecules
? mole ----------- 1.505 x10²³ molecules

1.505x10²³ / 6.02x10²³ => 0.25 moles

hope this helps!


4 0
3 years ago
Think about all that your feet do. They walk
Burka [1]

Answer:

squamous cells

basal cells

and melanocytes

7 0
2 years ago
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