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krok68 [10]
2 years ago
5

Does sodium fluoride follow the octet rule? If not, which exception is it?

Chemistry
1 answer:
krek1111 [17]2 years ago
3 0

Answer:

Sodium fluoride (NaF) does indeed follow the octet rule without any violations.

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What is the molarity of a solution containing 12.0 g of NaOH in 250.0 mL of solution?
riadik2000 [5.3K]

Answer:

1.196 M NaOH

Explanation:

Molarity = moles/Volume (L)

moles NaOH = mass NaOH/MM NaOH = 12/40.01 = 0.299 moles NaOH

Volume solution = 250 mL = 0.250L

M = 0.299/0.250=1.196 M NaOH

3 0
3 years ago
What is the average speed of a car that travels 540 miles in 6 hours?
Vitek1552 [10]
90 miles per hour. just divide 540 by 6
3 0
3 years ago
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These are large chemical compounds, primarily consisting of carbon and hydrogen, that exist in living organisms.
TEA [102]
It is called a Biomolecule
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3 years ago
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How many grams of Nacl would you need to prepare 200 ml of a 5 M SOLUTION. ?
vazorg [7]

Answer:

58.44 g of NaCl are needed.

Explanation:

Given data:

Mass of NaCl needed = ?

Volume of solution = 200 mL (200/1000 =0.2 L)

Molarity of solution = 5 M

Solution:

We will solve this problem through molarity formula.

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will put the values.

5 M = moles of solute / 0.2 L

Moles of solute = 5 mol/L × 0.2 L

Moles of solute = 1 mol

Mass of sodium chloride:

Mass = number of moles × molar mass

Mass = 1 mol × 58.44 g/mol

Mass = 58.44 g

Thus, 58.44 g of NaCl needed.

8 0
3 years ago
Write an equilibrium expression for each chemical equation involving one or more solid or liquid reactants or products.
Alex_Xolod [135]

Answer:

a.

Keq=\frac{[HCO_3^-][OH^-]}{[CO_3^{2-}]}

b.

Keq=[O_2]^3

c.

Keq=\frac{[H_3O^+][F^-]}{[HF]}

d.

Keq=\frac{[NH_4^+][OH^-]}{[NH_3]}

Explanation:

Hello there!

In this case, for the attached reactions, it turns out possible for us to write the equilibrium expressions by knowing any liquid or solid would be not-included in the equilibrium expression as shown below, with the general form products/reactants:

a.

Keq=\frac{[HCO_3^-][OH^-]}{[CO_3^{2-}]}

b.

Keq=[O_2]^3

c.

Keq=\frac{[H_3O^+][F^-]}{[HF]}

d.

Keq=\frac{[NH_4^+][OH^-]}{[NH_3]}

Regards!

5 0
3 years ago
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