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jolli1 [7]
3 years ago
10

A 40 kg skier starts at the top of a 12-meter high slope at the bottom she is traveling 10 m/s how much energy does she lose fri

ction?
A. she doesn't lose any because mechanical energy is always conserved
B. 4,704 J
C. 2,000 J
D. 2,704 J
Physics
2 answers:
Brrunno [24]3 years ago
8 0

Answer:

D. 2,704 J

Explanation:

I just took the quiz and got it right.

Please say thanks by putting a heart, so I know that I helped you

Iteru [2.4K]3 years ago
7 0
Potential energy at top:
PE = mgh
PE = 40 x 9.81 x 12
P.E = 4,708.8 J

Kinetic energy at bottom:
KE = 1/2 mv²
KE = 1/2 x 40 x 10²
K.E = 2,000 J

P.E = K.E + Frictional losses
Frictional losses = 4708 - 2000
Frictional losses = 2708 J

The answer is D.
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Copernicus preferred the heliocentric model.
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A force of constant magnitude pushes a box up a vertical surface, as shown in the figure.
Ray Of Light [21]

The work done on the box by the applied force is zero.

The work done by the force of gravity is 75.95 J

The work done on the box by the normal force is 75.95 J.

<h3>The given parameters:</h3>
  • Mass of the box, m = 3.1 kg
  • Distance moved by the box, d = 2.5 m
  • Coefficient of friction, = 0.35
  • Inclination of the force, θ = 30⁰

<h3>What is work - done?</h3>
  • Work is said to be done when the applied force moves an object to a certain distance

The work done on the box by the applied force is calculated as;

W = Fd cos(\theta)\\\\W = (ma)d \times cos(\theta)

where;

a is the acceleration of the box

The acceleration of the box is zero since the box moved at a constant speed.

W = (0) d \times cos(30)\\\\W = 0 \ J

The work done by the force of gravity is calculated as follows;

W = mg \times d\\\\W = 3.1 \times 9.8 \times 2.5 \\\\W = 75.95 \ J

The work done on the box by the normal force is calculated as follows;

W = (F_n) \times d\\\\W = (mg + F sin\theta) \times d\\\\W = (mg + 0) \times d\\\\W = mgd\\\\W = 3.1 \times 9.8 \times 2.5\\\\W = 75.95 \ J

Learn more about work done here: brainly.com/question/8119756

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2 years ago
Which postulate of relativity was supported by the experiments of Michelson and Morley
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Constancy of speed of light.
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3 years ago
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HELP!!!!!
andreev551 [17]

Answer:

Transverse Wave

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Longitudinal: vibrates in the same direction

Propagated: the direction the wave travels (specific to wave type)

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A 3.0-kg cylinder falls vertically from rest in a very tall, evacuated tube near the surface of the earth. What is its speed aft
alexandr1967 [171]

Answer:v=10.84 m/s

Explanation:

Given

mass of Cylinder m=3 kg

height of cylinder h=6 m

It is given that tube is evacuated so we can neglect air resistance so friction provided by the air is zero.

Since Energy cannot be destroyed but can be transformed from one form to another therefore Potential Energy of Cylinder is converted to Kinetic Energy of Cylinder

Potential Energy=mgh=3\times 9.8\times 6=176.4 J

Kinetic Energy =\frac{1}{2}mv^2=\frac{1}{2}\times 3\times (v)^2

176.4=\frac{1}{2}\times 3\times (v)^2

v=\sqrt{117.6}

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