Question

A 40 kg skier starts at the top of a 12-meter high slope at the bottom she is traveling 10 m/s how much energy does she lose friction?
A. she doesn't lose any because mechanical energy is always conserved
B. 4,704 J
C. 2,000 J
D. 2,704 J

Answer 1

Answer:

D. 2,704 J

Explanation:

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Answer 2

Potential energy at top:
PE = mgh
PE = 40 x 9.81 x 12
P.E = 4,708.8 J

Kinetic energy at bottom:
KE = 1/2 mv²
KE = 1/2 x 40 x 10²
K.E = 2,000 J

P.E = K.E + Frictional losses
Frictional losses = 4708 - 2000
Frictional losses = 2708 J

The answer is D.