Answer:
48 m/s
Explanation:
The time is 10 seconds
The speed of the car after 10 seconds when the relationship is 4.8 m/s^2 × time can be calculated as follows
= 4.8 × 10
= 48
Hence the speed is 48 m/s
I think the correct answer from the choices listed above is option C. The formula that would represent the speed of the Toyota would be <span>T+10 mph= 60 mph. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>
Assume distance of seperarion is 1m
F.elec = kQq/r^2
charge of a proton: 1.6×10^-19 C
charge of a neutron: 0 C
F.elec = 0 N
F.grav = GMm/r^2
mass of a proton: 1.672621898×10^-27 kg
mass of a neutron: 1.674927471×10^-27 kg
F.grav = (6.67408×10^-11)×(1.674927471×10^-27)×(1.672621898×10^-27)÷(1^2)
F.grav = 1.8699588×10^-64 N
