Answer:
The answer to your question is:
Explanation:
There are two kinds of cell transport passive transportation and active transportation.
Passive transportation does not need energy because molecules move from higher concentration to lower concentration.
Active transportation needs energy because molecules moves against concentration.
a. facilitated diffusion It's an example of passive transportation so this answer is wrong.
b. passive transport Molecules move in favor of concentration so this answer is wrong.
c. osmosis is another example of passive transport so this answer is wrong.
d. simple diffusion it's another example of passive transport, so it's wrong this answer.
e. active transport this is the right answer.
Answer:
Explanation:
Current is the rate of flow of charge.
Answer:
ω = 0.05 rad/s
Explanation:
We consider the centripetal force acting as the weight force on the surface of the cylinder. Therefore,
where,
ω = angular velocity of cylinder = ?
g = required acceleration = 9.8 m/s²
r = radius of cylinder = diameter/2 = 5.9 mi/2 = 2.95 mi = 4023.36 m
Therefore,
<u>ω = 0.05 rad/s</u>
Answer:
Tp/Te = 2
Therefore, the orbital period of the planet is twice that of the earth's orbital period.
Explanation:
The orbital period of a planet around a star can be expressed mathematically as;
T = 2π√(r^3)/(Gm)
Where;
r = radius of orbit
G = gravitational constant
m = mass of the star
Given;
Let R represent radius of earth orbit and r the radius of planet orbit,
Let M represent the mass of sun and m the mass of the star.
r = 4R
m = 16M
For earth;
Te = 2π√(R^3)/(GM)
For planet;
Tp = 2π√(r^3)/(Gm)
Substituting the given values;
Tp = 2π√((4R)^3)/(16GM) = 2π√(64R^3)/(16GM)
Tp = 2π√(4R^3)/(GM)
Tp = 2 × 2π√(R^3)/(GM)
So,
Tp/Te = (2 × 2π√(R^3)/(GM))/( 2π√(R^3)/(GM))
Tp/Te = 2
Therefore, the orbital period of the planet is twice that of the earth's orbital period.
Yes you are right cuz charging by friction cant be done in fluids( liquid and gas)
