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Mumz [18]
3 years ago
7

A toy train moves 40m in 20s at the constant velocity. What is the toy’s velocity? * 1 point

Physics
1 answer:
stepladder [879]3 years ago
7 0

Answer:

2 m/s

Explanation:

Velocity is a vector quantity that is given by:

v=\frac{d}{y}

where

d is the displacement of the object (a vector indicating its change in position)

t is the time elapsed

Note that since velocity is a vector, it has both a magnitude and a direction (the same as the displacement).

For the toy train in this problem, we have:

d = 40 m (displacement)

t = 20 s (time elapsed)

So, its velocity is:

v=\frac{40}{20}=2 m/s

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8. A student does 1,000 J of work when she moves to her dormitory. Her internal energy is decreased by 3,000 J. Determine the he
Lyrx [107]

Answer:

The heat loss during the process = -4000 J

Explanation:

Work done by the student (W) = - 1000 J

Negative sign on the system is due to work done on the system.

Decrease in internal energy (U) = - 3000 J

We know that heat transfer in the system is given by (Q) = U + W

⇒ Q = - 1000 - 3000

⇒ Q = - 4000 J

This is the value of heat transfer during the process And negative sign indicates that heat loss during the process.

6 0
3 years ago
Each croquet ball in a set has a mass of 0.53 kg. The green ball, traveling at 14.4 m/s, strikes the blue ball, which is at rest
faust18 [17]

a) 14.4 m/s

The problem can be solved by using the law of conservation of total momentum; in  fact, the total initial momentum must be equal to the final total momentum:

p_i = p_f

So we have:

m_g u_g + m_b u_b = m_g v_g + m_b v_b (1)

where

m_b = m_g = m = 0.53 kg is the mass of each ball

u_g = 14.4 m/s is the initial velocity of the green ball

u_b = 0 is the initial velocity of the blue ball

v_g=0 is the final velocity of the green ball

v_b is the final velocity of the blue ball

Simplifying the mass in the equation and solving for v_b, we find

v_b = u_g = 14.4 m/s

b) 12.0 m/s

This time, the green ball continues moving after the collision at

v_g = 2.4 m/s

So the equation (1) becomes

u_g = v_g + v_b

And solving for v_b we find

v_b = u_g - v_g = 14.4 m/s-2.4 m/s=12.0 m/s

c) 13.5 m/s

This time, the green ball continues moving after the collision at

v_g = 0.9 m/s

So the equation (1) becomes

u_g = v_g + v_b

And solving for v_b we find

v_b = u_g - v_g = 14.4 m/s-0.9 m/s=13.5 m/s

8 0
2 years ago
Between which two points did they travel fastest?
marusya05 [52]

Answer:

During the section CD , the speed is fastest.

Explanation:

The rate of change of distance is called speed.

Speed = distance / time

Its SI unit ism/s. It is a scalar quantity.

The slope of the distance time graph is given by the speed of the object.

Here, the speed of AB is 30/3= 10 m/s .

The speed of BC is = 0 m/s

The speed of CD is (50 - 30)/(6 - 5) = 20 m/s

So, the speed is maximum during the section CD.

7 0
3 years ago
2. A ladder 16cm long weighs 420N and it's centre of gravity is 7m from one end.It is carried horizontally by two boys,each hold
ipn [44]

Answer:

well the answers are 180 and 240 obviously

Explanation:

Download pdf
8 0
2 years ago
Read 2 more answers
A ball rolls from 10 m to -25 m in 2.5 seconds. What was<br> its average velocity?<br> (Units = m/s)
marissa [1.9K]

Answer:

v = -14 m/s

Explanation:

Given that,

Initial location of the ball, X₁ = 10 m

Final position of the ball,  X₂ = -25 m

Time taken to travel is, t = 2.5 s

The average velocity of the ball is given by the formula,

                       V = X₂ - X₁ / t     m/s

Substituting the values in the above equation,

                       V = -25 - 10 / 2.5

                          = -14 m/s

The negative sign in the velocity indicates that ball rolls in the opposite direction.

Hence, the average velocity of the ball is  v = -14 m/s

8 0
3 years ago
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