Answer:
The heat loss during the process = -4000 J
Explanation:
Work done by the student (W) = - 1000 J
Negative sign on the system is due to work done on the system.
Decrease in internal energy (U) = - 3000 J
We know that heat transfer in the system is given by (Q) = U + W
⇒ Q = - 1000 - 3000
⇒ Q = - 4000 J
This is the value of heat transfer during the process And negative sign indicates that heat loss during the process.
a) 14.4 m/s
The problem can be solved by using the law of conservation of total momentum; in fact, the total initial momentum must be equal to the final total momentum:

So we have:
(1)
where
is the mass of each ball
is the initial velocity of the green ball
is the initial velocity of the blue ball
is the final velocity of the green ball
is the final velocity of the blue ball
Simplifying the mass in the equation and solving for
, we find

b) 12.0 m/s
This time, the green ball continues moving after the collision at

So the equation (1) becomes

And solving for
we find

c) 13.5 m/s
This time, the green ball continues moving after the collision at

So the equation (1) becomes

And solving for
we find

Answer:
During the section CD , the speed is fastest.
Explanation:
The rate of change of distance is called speed.
Speed = distance / time
Its SI unit ism/s. It is a scalar quantity.
The slope of the distance time graph is given by the speed of the object.
Here, the speed of AB is 30/3= 10 m/s .
The speed of BC is = 0 m/s
The speed of CD is (50 - 30)/(6 - 5) = 20 m/s
So, the speed is maximum during the section CD.
Answer:
well the answers are 180 and 240 obviously
Explanation:
Answer:
v = -14 m/s
Explanation:
Given that,
Initial location of the ball, X₁ = 10 m
Final position of the ball, X₂ = -25 m
Time taken to travel is, t = 2.5 s
The average velocity of the ball is given by the formula,
V = X₂ - X₁ / t m/s
Substituting the values in the above equation,
V = -25 - 10 / 2.5
= -14 m/s
The negative sign in the velocity indicates that ball rolls in the opposite direction.
Hence, the average velocity of the ball is v = -14 m/s