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VashaNatasha [74]

3 years ago

5

What is systematic error

2 answers:

julsineya [31]3 years ago

4 0

Answer: an error

Explanation:

IgorC [24]3 years ago

4 0

Answer:

A consistent, repeatable error that isn't random. Usually associated with faulty equipment and the like.

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Gravity prevents planets from flying off at a

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Answer:elliptical orbit

Explanation:

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2 years ago

A moving object must have which type of energy

xxMikexx [17]

Answer:

Kinetic Energy

Explanation:

Kinetic energy is the energy an object has because of its motion. If we want to accelerate an object, then we must apply a force. ... Kinetic energy can be transferred between objects and transformed into other kinds of energy. For example, a flying squirrel might collide with a stationary chipmunk.

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3 years ago

Label the sound wave- amplitude, wavelength, crest, trough

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A - Crest, B - amplitude, C - wavelength, D - trough

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2 years ago

What are some examples and non-examples of volume

Jlenok [28]

Answer:

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3 years ago

Read 2 more answers

Consider a block on frictionless ice. Starting from rest, the block travels a distance din

sweet [91]

Answer:

<em>The distance is now 4d</em>

Explanation:

<u>Mechanical Force</u>

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

F = m.a

Where a is the acceleration of the object.

The acceleration can be calculated by solving for a:

$\displaystyle a=\frac{F}{m}$

Once we know the acceleration, we can calculate the distance traveled by the block as follows:

$\displaystyle d = vo.t+\frac{at^2}{2}$

If the block starts from rest, vo=0:

$\displaystyle d = \frac{at^2}{2}$

Substituting the value of the acceleration:

$\displaystyle d = \frac{\frac{F}{m}t^2}{2}$

Simplifying:

$\displaystyle d = \frac{Ft^2}{2m}$

When a force F'=4F is applied and assuming the mass is the same, the new acceleration is:

$\displaystyle a'=\frac{4F}{m}$

And the distance is now:

$\displaystyle d' = \frac{4Ft^2}{2m}$

Dividing d'/d:

$\displaystyle \frac{d' }{d}=\frac{\frac{4Ft^2}{2m}}{\frac{Ft^2}{2m}}$

Simplifying:

$\displaystyle \frac{d' }{d}=4$

Thus:

d' = 4d

The distance is now 4d

3 0

2 years ago