Find the left critical value for 95% confidence interval for σ with n = 41. 26.509 24.433 55.758 59.342
1 answer:
Answer: 59.342
Step-by-step explanation:
The chi-square critical values are used to find the confidence interval for σ.
Left critical value = [i.e. chi-square value from chi-square table corresponding to degree of freedom n-1 and significance level of
]
To find : left critical value for 95% confidence interval for σ with n = 41.
Significance level :
degree of freedom = 41-1=40
Now, the left critical value for 95% confidence interval for σ with n = 41 is the chi-square value corresponding to degree of freedom n-1 and
=59.342 [from chi-square table ]
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Hope this helped! c:
Hope this helped! c:
Answer:
The answer is below
Step-by-step explanation:
The empirical rule states for a normal distribution, 68% of the data falls within one standard deviation, 95% falls within two standard deviations and 99.7% falls within three standard deviations.
z score is given by:
Given that mean (μ) = 42 ounces, standard deviation (σ) = 10 ounces.
a) 99.7% falls within three standard deviations. Therefore:
99.7% falls within μ ± 3σ = 42 ± 3(10) = 42 ± 30 = (12, 72)
Therefore 99.7% falls within 12 ounce and 72 ounce.
b) For x > 26
For x < 66
From the normal distribution table, P(26 < x < 66) = P(-1.6 < z < 2.4) = P(z < 2.4) - P(z < -1.6) = 0.9918 - 0.0548 = 0.937 = 93.7%
c) For x > 34
From the normal distribution table, P(x > 34) = P(z > -0.8) = 1 - P(z < -0.8) = 1 - 0.2119 = 0.7881 = 78.81%