Correct answer is 
.
Phosphoric acid is a polyprotic acid having 3 acidic hyrdogen therefore it will have 3 pka values.
The equations for the release of acidic hydrogen can be written as:
From the pka values we can judge the idea of pH as using Henderson-Hasselbalch Equation, we get the relation between pH and pka.
Using the following equation, relation of pH and pka is
![pH=pka+log\frac{[A^-]}{HA}](https://tex.z-dn.net/?f=pH%3Dpka%2Blog%5Cfrac%7B%5BA%5E-%5D%7D%7BHA%7D)
Using this equation, we can find that the equation having pka= 2. 14 is closest to the pH=3.2 so the ionic form in this equation will be dominant at the same pH.
Therefore at pH=3.2 the ionic form of 
is dominant.
Answer:
Explanation:
From the question we are told that:
Edge length of the unit cell 
a)
Generally the equation for The relationship between edge length and radius is mathematically given by
Therefore
b)
From the question we are told that:
Density 
Edge length of 
Therefore Volume is given as
Generally the equation for Mass is mathematically given by
Therefore Molarity is given as
Finally The atoms in a unit cell is
Answer:
the sum of the atoms or ions in the compound
Answer: 
or Sodium carbonate.
or Potassium permanganate
Sodium ion carries 1 + charge whereas carbonate ion carries overall charge of -2. So for every carbonate ion, two sodium ions combine to balance the charges and thus form a stable compound,
Potassium ion carries 1 + charge where as permanganate ion carries overall charge of -1. So for every permanganate ion, one potassium ion combines to balance the charges and thus form a stable compound,
The predicted formulas are shown in the attached image.
In this question, XB3(aq) is an ionic compound which will have the releasing of 3 B⁻ ions ions in water for every molecule of XB3 that dissolves.
XB3(s) --> X+(aq) + 3 B⁻(aq)
[B⁻] = 0.22 mol XB3/1L × 3 mol B⁻ / 1 mol XB3 = 0.66 M
The answer to this question is [B⁻] = 0.66 M
