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Anvisha [2.4K]
3 years ago
6

Ice floats on water because ice is less dense than water. How is this helpful to fish that live in a lake?. . A.It shades the fi

sh from the sun.. B.It keeps the fish warm in the winter.. C.It helps the fish stay cold in the winter.. D.It blocks oxygen from reaching the water..
Physics
2 answers:
ra1l [238]3 years ago
5 0

Answer:

option B is true . It keeps the fish warm in the winter.

Explanation:

As the density of ice less than water so it floats on the surface of water. The temperature inside the water is more than the surface so he fishes swim inside the water and becomes warm in winters.

Phantasy [73]3 years ago
3 0
"It <span>keeps the fish warm in the winter" is the choice among the choices given in the question that shows how it is helpful to fish that lives in a lake water. The correct option among all the options that are given in the question is the second option or option "B". I hope the answer has helped you.</span>
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A piece of metal weighing 59.047 g was heated to 100.0 °C and then put it into 100.0 mL of water (initially at 23.7 °C). The met
saul85 [17]

Answer: Law of conservation of energy

Heat Loss by the metal  = Heat Gain by the water  (Assume no heat loss to the environment)

M₁C₁ΔT₁= M₂C₂ΔT₂

Where

C₁ and C₂ = the specific heat capacities of the metal and water = C₁?, 4.182J/gK

ΔT₁ and ΔT₂ = Temperature changes of the metal and the water

ΔT₁ = (373 - 300.8)K and ΔT₂= (300.8 - 296.7)K   convert to S.I units

M₁ and M₂ are the masses of the metal and water = 59.047g, but

M₂ = density x volume = 1kg/m³ x 0.1m³=0.1kg

Note: Volume of water = 100ml=0.1m³, also density of water = 1kg/m³

We have,

0.059kg x C₁J/KgK (373 - 300.8)K = 0.1kg x 4182J/kgK (300.8 - 296.7)K

4.259C₁=1715J/KgK

C₁=402.5J/KgK

The specific heat of the metal is 402.5J/KgK

3 0
3 years ago
A strip of copper 150 µm thick and 4.50 mm wide is placed in a uniform magnetic field of magnitude B = 0.74 T, that is perpendic
Sophie [7]

Answer:

V = 6.55*10^{-6} v

Explanation:

The number density can be determined by using below formula:

n = \frac{Bi}{Vle}

where,

B  is uniform magnetic field 0.74

i is current 18 A

V is hall potential difference

l is thickness 150 MICRO METER

e is electron charge 1.6 *10^{-19} C

therefore V can be determined as

V = \frac{iB}{nle}

V = \frac{18*0.74}{8.47*10^{28}*150*10^{-6}*1.6 *10^{-19}}

V = 6.55*10^{-6} v

8 0
3 years ago
The built-up beam is formed by welding together the thin plates of thickness 5 mm. determine the location of the shear center o.
atroni [7]

Answer:

The location of the shear center o is 0.033 or 33 m

Explanation:

Solution

Recall that,

The moment of inertia of the section is =  I = 0.05 * 0.4 ^3 /12 + 0.005 * 0.2 ^3/12

= 30 * 10 ^ ⁻⁶ m⁴

Now,

The first moment of inertia is

Q =ῩA = [ (0.1 -x) + x/2] (0.005 * x)

= 0.5x * 10 ^⁻³ - 2.5 x * 10⁻³ x²

Thus,

The shear flow is,

q =  VQ/I

so,

P =  (0.5x * 10 ^⁻³ - 2.5 x * 10⁻³ x²)/ 30 * 10 ^⁻⁶

P = (16.67 x - 83. 33  x²)

The shear force resisted by the shorter web becomes

Vw,₂ = 2∫ = ₀.₁ and ₀ = P (16.67 x - 83. 33  x²) dx = 0.11x

Then,

We take the moment at a point A

∑Mₐ = 0

- ( p * e)- (Vw₂ * 0.3 ) = 0

e =  0.11 p * 0.3/p

which gives us 0.033 m

= 33 m

Therefore the location of the shear center o is 0.033 or 33 m

Note: Kindly find an attached diagram to the question given above as part of the explanation solved with it.

4 0
3 years ago
A railroad car of mass M moving at a speed v1 collides and couples with two coupled railroad cars, each of the same mass M and m
marshall27 [118]

Answer:

vf = v₁/3 + 2v₂/3

Explanation:

Using the law of conservation of linear momentum,

momentum before impact = momentum after impact

So, Mv₁ + 2Mv₂ = 3Mv (since the railroad cars combine) where v₁ = initial velocity of first railroad car, v₂ = initial velocity of the other two coupled railroad cars, and vf = final velocity of the three railroad cars after impact.

Mv₁ + 2Mv₂ = 3Mvf

dividing through by 3M, we have

v₁/3 + 2v₂/3 = vf

vf = v₁/3 + 2v₂/3

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3 years ago
The path of electric current is known as___
777dan777 [17]

here the answer to your question hope it helps you

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7 0
3 years ago
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