Na₂S(aq) + Cd(NO₃)₂(aq) = CdS(s) + 2NaNO₃(aq)
v=25.00 mL
c=0.0100 mmol/mL
M(Na₂S)=78.046 mg/mmol
n(Na₂S)=n{Cd(NO₃)₂}=cv
m(Na₂S)=M(Na₂S)n(Na₂S)=M(Na₂S)cv
m(Na₂S)=78.046*0.0100*25.00≈19.5 mg
Answer:
Altogether for both models; two red jellybeans, two white jellybeans, two black jellybeans and six blue jellybeans.
<em>Note: Since no specific color was stated for oxygen atoms, the answer assigns blue colored jellybeans to represent oxygen atoms.J</em>
Explanation:
Sodium bicarbonate, NaHCO₃ is a compound composed of one atom of sodium, one atom of hydrogen, one atom of carbon and three atoms of oxygen.
Since red jellybeans represent sodium atoms, white jellybeans represent hydrogen atoms, black jellybeans represent carbon atoms and blue jellybeans represent oxygen atoms, each of the two students will require the following number of each jellybean for their model of sodium carbonate: One red jellybean, one white jellybean, one black jellybean and three blue jellybeans.
Altogether for both models; two red jellybeans, two white jellybeans, two black jellybeans and six blue jellybeans.
Answer:
Explanation:
The changes in properties from metals to non-metals on a periodic table can be measured and determined by the metallicity or electropositivity of elements.
Metallicity is a measure of the tendency of atoms of an element to lose electrons.
a.
Down a periodic group, metallicity increases.
b.
Across a period from left to right electropositivity or metallicity decreases.
Metals are found in the left part of periodic table and the most reactive metal sits in the lower left corner. Non-metals are towards the right side of the table.
Analytical chemistry studies and uses instruments and methods used to separate, identify, and quantify matter
1. Pressure decreases with increasing volume as the increased volume increases space for molecules to move around, thus decreasing the collisions and decreasing pressure.
2. A has a higher pressure given that the higher the n value, or moles present, the higher the pressure will be if everything else is held constant.
3. Gases have weaker intermolecular forces than liquids and solids.
4. Pressure must be 1/2, or 0.5 as PV=k, (P)(4)=(2), (P)=(2/4)
5. 2.25 L
6. Increasing space will decrease collisions and vice versa
7. 1122 2L bottles
8. 2.35 L
9. 2.1428 L
10. It would expand as they are directly proportional
11. 2.14959 L
12. 546K
13. .003663 atm`K
14. If pressure and temperature are directly proportional, then they increase or decrease at a constant rate
15. quadruples as they are directly proportional
16. 18.9963587 atm
Sorry hun, I gotta go. Good luck!
