The answer is 57.14%.
First we need to calculate molar mass of <span>NaHCO3. Molar mass is mass of 1 mole of a substance. It is the sum of relative atomic masses, which are masses of atoms of the elements.
Relative atomic mass of Na is 22.99 g
</span><span>Relative atomic mass of H is 1 g
</span><span>Relative atomic mass of C is 12.01 g
</span><span>Relative atomic mass of O is 16 g.
</span>
Molar mass of <span>NaHCO3 is:
22.99 g + 1 g + 12.01 g + 3 </span>· <span>16 g = 84 g
Now, mass of oxygen in </span><span>NaHCO3 is:
3 </span>· 16 g = 48 g
mass percent of oxygen in <span>NaHCO3:
48 g </span>÷ 84 g · 100% = 57.14%
Therefore, <span>the mass percent of oxygen in sodium bicarbonate is 57.14%.</span>
Answer:
protons = atomic numbermass number = protons + neutronsatomic number = mass number - neutrons = 78-38 = 40
Explanation:
Oxidation half reaction is written as follows when using using reduction potential chart
example when using copper it is written as follows
CU2+ +2e- --> c(s) +0.34v
oxidasation is the loos of electron hence copper oxidation potential is as follows
cu (s) --> CU2+ +2e -0.34v
I choose question 1, so molarity is the concentration of a soulution expressed as the number of moles of solute by the litress of soulution. to get molarity you divide the moles of soulute by the litress of solution. soo 1 calculate the number of moles of solute present. 2 Calculate the number of litress solution present. 3. divide the number of moles of solute by the number of litress of solution
soo 1 mol of NaOH has a mass of 40.00 g, so moles of NaOH= 26.7. 1 mole divided 40.00 = 0.375. litress of solution = 650 g. im not sure why its a g i usally do it Ls so i guess its the way your teacher wants you to do it so do you know how to do that. so molarity = moles of solute and litress solution. sorry this probably didnt help i just wanted to add something that might help. im still working on this stuff myself hope this helps.
Answer:
The correct would be C i think :)
Explanation:
Stay postivie :)
