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stellarik [79]
3 years ago
9

All + HgCl, --------> AICI,

Chemistry
1 answer:
Free_Kalibri [48]3 years ago
5 0

Answer:

64.7g

Explanation:

The balanced chemical equation of this question is as follows;

AlI + HgCl2 → HgI + AlCl2

Based on the above equation, 1 mole of AlI (aluminum monoiodide) reacts to produce 1 mole of HgI (mercury iodide).

Using mole = mass/molar mass to convert mass of HgI to moles.

Molar mass of HgI = 200.59 + 127

= 327.59g/mol

Mole = 138/327.59

= 0.42mol

- If 1 mole of AlI (aluminum monoiodide) reacts to produce 1 mole of HgI (mercury iodide)

- Then 0.42 mol of HgI will be produced by 0.42mol of AlI.

Using mole = mass/molar mass

Mass = mole × molar mass

Molar mass of AlI = 27 + 127

= 154g/mol

Mass of AlI = 0.42 × 154

= 64.7g of AlI

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What does this do to the electrons outside the nucleus in the gaseous atoms
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Explanation:

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X

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3 years ago
Calculate the molarity of a solution of sodium hydroxide, naoh, if 23.64 ml of this solution is needed to neutralize 0.5632 g of
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The  molarity  of  NaOH  needed  is  calculated   as  follows
calculate  the  moles  of  KhC8h4O4

that  is  moles  =  mass/molar  mass  of  KhC8h4O4(204.22 g/mol)

=0.5632g /204.22g/mol=  2.76  x10^-3  moles

write the  equation  for  reaction

khc8h4O4  +  NaOH  ---> KNaC8h4O4  +  H2O

from  the  equation  above  the   reacting  ratio   of   KhC8h4O4  to  NaOh  is  1:1  therefore  the  moles  of  Naoh  is  also  2.76  x10^-3  moles

molarity  of NaOh  =  (moles  of  NaOh /  volume ) x  1000

that  is { (2.76  x10^-3) / 23.64}  x100  =0.117 M
8 0
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