Answer:
The Relative Formula Mass of Fe(NO₃)₂ is 179.8524 grams
Explanation:
The Relative Formula Mass is the mass of one mole of a compound expressed in grams, obtained by adding together the Relative Atomic Masses, RAM, of the elements which makes the compound
The Relative Formula Mass of a compound is the same as its Relative Molecular Mass
The relative formula mass of Fe(NO₃)₂ is given as follows;
The relative atomic mass of Fe = 55.845 amu
The relative atomic mass of nitrogen, N = 14.0067 amu
The relative atomic mass of oxygen, O = 15.999 amu
Therefore, we have;
The formula mass of Fe(NO₃)₂ = (55.845 + 2×(14.0067 + 3×15.999)) amu = 179.8524 amu
The Relative Formula Mass of Fe(NO₃)₂ = 179.8524 grams.
Multiply .800 moles of O2 by Avagadro's number divided by 1 mole. This will get rid of the moles on the bottom and leave you with molecules. So technically .800 times 6.02x10^23.
The amount of the original isotope that remains after 30 days is 11.14.
<h3>What is the half life?</h3>
The half life of a radioactive nuclide has to do with the time that it takes for only half of the original number of nuclides to remain.
Now;
No = 150 grams
N = ?
t1/2 = 8 days
t = 30 days
Then;
N/No = (1/2)^t/t1/2
N/150 = (1/2)^30/8
N/150 = (1/2)^3.75
N = (1/2)^3.75 * 150
N = 11.14
Learn more about half life:brainly.com/question/24710827
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Answer:
5.90, 11.8, 47.2
Explanation:
Let’s remove the parentheses and write the formula as MgCl₂O₈.
We see that 1 mol Mg(ClO₄)₂ contains 1 mol Mg atoms, 2 mol Cl atoms, and 8 mol O atoms.
∴
∴ Mg, Cl, O = 5.90, 11.8, 47.2