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ANEK [815]
3 years ago
15

What is this material

Chemistry
1 answer:
faltersainse [42]3 years ago
3 0

Answer:

rocks

Explanation:

rocks are solid in nature and it contains essential nutrients but can break down by the process called weathering

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(a) What characteristic functional group do you expect to see in the IR spectrum, that is indicative of eugenol? (b) What wavenu
Darina [25.2K]

Answer:

a) The functional group that will be evident in the IR spectrum is the OH group.

b) OH group appears between 3200-3600 cm⁻¹

c) An important impurity that have the same functional group is water.

Explanation:

Eugenol is a chemical substance that consist in a benzene that have in 1 an alcohol, in position 2 a methyl ether and in position 4 an 1-propene bonded by the terminal alkyl carbon.

a) Having this in mind, the functional group that will be evident in the IR spectrum is the OH group.

b) This OH group appears between 3200-3600 cm⁻¹

c) An important impurity that have the same functional group is water. When you have water in your sample a big signal will appear in this zone and it is possible that overlapes the OH signal of eugenol.

I hope it helps!

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4 years ago
Sodium (Na) A Homogeneous Mixture B Element C Compound D Heterogeneous Mixture
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Sodium is categorized as a B. Element.
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What are the two parts of a solution?
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The 2 parts or components that make up a solution would be the solute and the solvent.
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Convert 0.74Kcal/min to cal/sec
professor190 [17]
<span>0.74 Kcal/min x 1000 cal/60 s         


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Water is flowing in a pipe with a mass flow rate of 100.0 lb/h (M water H,O=18.016). What is the (i) Molar flow rate of H20 (gmo
Arada [10]

Answer:

i) 0,7 molH20/s

ii)11,2 g O/s

iii)1,4 g H/s

Explanation:

i) To find the molar flow rate of water, we just convert the mass of water to moles of water using its molecular weight(g/mol) and changing to the proper units (lb to grames and hours to seconds):

100 \frac{lb}{h}*\frac{453,5g}{1 lb}*\frac{1molH20}{18,016g}*\frac{1h}{3600s}=0,7\frac{molH20}{s}

ii) Now we just consider the oxygen in the water stream (for 1 mole of water there is 1 mole of oxygen):

100\frac{lb}{h} *\frac{453,5g}{1lb}*\frac{1 molH20}{18,016g}*\frac{1molO}{1molH20}*\frac{16gr}{1molO}*\frac{1h}{3600s}=11,2\frac{gO}{s}

iii)Just considering the hydrogen in the stream (for 1 mole of water there is 2 moles of hydrogen):

100\frac{lb}{h} *\frac{453,5g}{1lb}*\frac{1 molH20}{18,016g}*\frac{2molH}{1molH20}*\frac{1gr}{1molH}*\frac{1h}{3600s}=1,4\frac{gH}{s}

3 0
3 years ago
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