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blondinia [14]
3 years ago
6

Please answer this correctly

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
6 0

Answer:

Opinion

Step-by-step explanation:

This is an opinion because it says "more exciting to visit than"

This implies the persons' own beliefs and is not a fact, because this is not true for everyone

You might be interested in
Find the measure of each angle (in degrees) of
d1i1m1o1n [39]

Answer:

∠A = 88°

∠B = 92°

∠C = 88°

∠D = 92°

Step-by-step explanation:

∠A + ∠B = 180°

(2x + 4) + (3x - 34) = 180

reduce:

5x - 30 = 180

5x = 210

x = 42

∠A = 2(42) + 4 = 88°

∠B = 3(42) -34 = 92°

∠C = ∠A = 88°

∠D = ∠B = 92°

3 0
3 years ago
H = vt - 16t^2, solve for v
Sophie [7]
H=vt-16t²
vt-16t²=H
vt=16t²+H
v=(16t²+H)/t
v=16(t²/t)+H/t
v=16t+H/t

Answer: the answer would be: v=16t+H/t
4 0
3 years ago
There are 14 juniors and 16 seniors in a chess club. a) From the 30 members, how many ways are there to arrange 5 members of the
Dmitrij [34]

Answer:

a) 17,100,720

b) 4,717,440

c) 10,920

d) 2821

Step-by-step explanation:

14 juniors and 16 seniors = 30 people

a) From the 30 members, how many ways are there to arrange 5 members of the club in a line?

As it is a ordered arrangement

30.29.28.27.26 = 17,100,720

b) How many ways are there to arrange 5 members of the club in a line if there must be a senior at the beginning of the line and at the end of the line?

16.28.27.26.15 = 4,717,440

c) If the club sends 2 juniors and 2 seniors to the tournament, how many possible groupings are there?

Not ordered arrangement. And means that we need to multiply the results.

C₁₄,₂ * C₁₆,₂

C₁₄,₂ = <u>14.13.12!</u> = <u>14.13 </u>= 91

           12! 2!            2    

C₁₆,₂ = <u>16.15.14!</u> = <u>16.15 </u>= 120

           14! 2!            2    

C₁₄,₂ * C₁₆,₂ = 91.120 = 10,920

d) If the club sends either 4 juniors or 4 seniors, how many possible groupings are there?

Or means that we need to sum the results.

C₁₄,₄ + C₁₆,₄

C₁₄,₄ = <u>14.13.12.11.10!</u> = <u>14.13.12.11 </u>= 1001

                  10! 4!               4.3.2.1    

C₁₆,₄ = <u>16.15.14.13.12!</u> = <u>16.15.14.13 </u>= 1820

                  12! 4!               4.3.2.1    

C₁₄,₄ + C₁₆,₄ = 1001 + 1820 = 2821

7 0
3 years ago
Find the Z-scores that separate the middle 61% of the distribution from the area in the tails of the standard normal distributio
professor190 [17]

Answer:

Z-scores between -0.86 and 0.86 separate the middle 61% of the distribution from the area in the tails of the standard normal distribution

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Middle 61%

Between the 50 - (61/2) = 19.5th percentile and the 50 + (61/2) = 80.5th percentile.

19.5th percentile.

Z with a pvalue of 0.195. So Z = -0.86

80.5th percentile.

Z with a pvalue of 0.805. So Z = 0.86.

Z-scores between -0.86 and 0.86 separate the middle 61% of the distribution from the area in the tails of the standard normal distribution

8 0
3 years ago
A pound of rice crackers costs $2.88.Matthew purchases 1/4 pound of crackers.How much will he pay?
Sergio [31]

Answer: $0.72


Step-by-step explanation: $2.88/4


3 0
3 years ago
Read 2 more answers
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