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USPshnik [31]
3 years ago
15

Why is the Big Bang a theory and not a fact

Physics
2 answers:
Ludmilka [50]3 years ago
7 0
Because it has not been proven. We have no evidence that the big bang happened. 
choli [55]3 years ago
7 0
Because we do not yet have enough proof. The Big Bang (theoretically) happened over 10 billion years ago, and as of now we are not sure of what really happened, but we can be quite sure.
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An element's atomic number is 34. How many protons would an atom of this element have?
Elena-2011 [213]

34. The element would have 34 protons. Also 34 electrons.

7 0
3 years ago
a ball is thrown straight up it passes a 2.00 m high window 7.5 meters off the ground on its path up it takes 1.3 s to go past t
Svet_ta [14]
Let's say the velocity at the bottom of the window was "v."
s = v*t + ½at²
2 m = v * 1.3s - 4.9m/s² * (1.3s)² = v * 1.3s - 8.3 m
v = 10.3m / 1.3s = 7.9 m/s

Then the initial speed was
V = √(v² + 2as) = √(7.9m/s² + 2 * 9.8m/s² * 7.5m) = 14 m/s ◄ initial velocity
(after rounding to 2 digits from 14.5 m/s).
8 0
3 years ago
If there is 10% sales tax on a car costing $18,000
MaRussiya [10]

Answer:

180

Explanation:

i think

6 0
3 years ago
Read 2 more answers
Which of newtons laws accounts for the following statement " Negative acceleration is proportional to applied braking force "
fenix001 [56]
I believe that would be his second law!
4 0
4 years ago
The electric force between two charged objects of charge +Q0 that are separated by a distance R0 is F0. The charge of one of the
vovikov84 [41]

Answer:

F=3F_o(\frac{R_o}{R_{o2}})^2

Explanation:

This problem is approached using Coulomb's law of electrostatic attraction which states that the force F of attraction or repulsion between two point charges, Q_1 and Q_2 is directly proportional to the product of the charges and inversely proportional to the square of their distance of separation R.

F=\frac{kQ_1Q_2}{R^2}..................(1)

where k is the electrostatic constant.

We can make k the subject of formula  as follows;

k=\frac{FR^2}{Q_1Q_2}...........(2)

Since k is a constant, equation (2) implies that the ratio of the product of the of the force and the distance between two charges to the product of charges is a constant. Hence if we alter the charges or their distance of separation and take the same ratio as stated in equation(2) we will get the same result, which is k.

According to the problem, one of the two identical charges was altered from Q_o to 3Q_o and their distance of separation from R_o to R_{o2}, this also made the force between them to change from F_o to F_{o2}. Therefore as stated by equation (2), we can write the following;

\frac{F_oR_o^2}{Q_o*Q_o}=\frac{F_{o2}R_{o2}^2}{3Q_o*Q_o}.............(3)

Therefore;

\frac{F_oR_o^2}{Q_o^2}=\frac{F_{o2}R_{o2}^2}{3Q_o^2}.............(4)

From equation (4) we now make the new force F_{o2} the subject of formula as follows;

{F_oR_o^2}*{3Q_o^2}=F_{o2}R_{o2}^2*{Q_o^2}

Q_o then cancels out from both side of the equation, hence we obtain the following;

3{F_oR_o^2}=F_{o2}R_{o2}^2.............(4)

From equation (4) we can now write the following;

F_{o2}=\frac{3F_oR_o^2}{R_{o2}^2}

This could also be expressed as follows;

F_{o2}=3F_o(\frac{R_o}{R_{o2}})^2

3 0
4 years ago
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