1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kozerog [31]
2 years ago
8

Help?? ....... ┐(‘~`;)┌​

Physics
2 answers:
7nadin3 [17]2 years ago
8 0

Answer:

(3) Both extensional as well as compressional strain is produced

Explanation:

Serggg [28]2 years ago
8 0

Both extensional as well as compressional strain is produced

  • Strain is amount of restoration formed by a restoring force .
  • It is formed in the direction of force applied.
You might be interested in
Why doesn't the skateboarder rolls as high up the ramp each time you go down the ramp ​
Alexandra [31]
Because of the law of inertia and it’s effect on the skater
5 0
3 years ago
Which is the largest gas that occurs in our atmosphere?
Mademuasel [1]

Answer:

OXYGEN

Explanation:brainlyist me

6 0
3 years ago
Read 2 more answers
A 97 kg man lying on a surface of negligible friction shoves a 62 g stone away from himself, giving it a speed of 2.6 m/s. What
tangare [24]

Answer:

man will move in opposite direction with speed

v_1 = 1.66 \times 10^{-3} m/s

Explanation:

As we know that man is lying on the friction-less surface

so here net force along the surface is zero

so if we take man + stone as a system then net change in momentum of this system will become zero

so here we have

P_i = P_f

0 = m_1v_1 + m_2v_2

here we have

0 = (97)v_1 + 0.062(2.6)

v_1 = -\frac{0.1612}{97}

v_1 = -1.66 \times 10^{-3} m/s

3 0
3 years ago
The mass of a planet is 3.7 x 1024 kg. If the planet has a radius of 9.2 x 106 m what is the acceleration of gravity for a perso
nalin [4]

Explanation:

It s given that,

Mass of a planet, M=3.7\times 10^{24}\ kg

Radius of a planet, R=9.2\times 10^{6}\ m

(1) We need to find the acceleration due to gravity for a person on the surface of the planet. Its formula is given by :

g=\dfrac{GM}{R^2}

g=\dfrac{6.67\times 10^{-11}\ Nm^2/kg^2\times 3.7\times 10^{24}\ kg}{(9.2\times 10^{6}\ m)^2}

g=2.91\ m/s^2

(2) The escape velocity is given by :

v=\sqrt{\dfrac{2GM}{R}}

v=\sqrt{{\dfrac{2\times 6.67\times 10^{-11}\ Nm^2/kg^2\times 3.7\times 10^{24}\ kg}{9.2\times 10^{6}\ m}}

v = 7324.61 m/s

Hence, this is the required solution.

3 0
3 years ago
If earth were a ping pong what size ball would jupiter be
Mariulka [41]

Answer:

a large beach ball

Explanation:

6 0
3 years ago
Other questions:
  • Use Hooke's Law and Newton's 2nd Law to derive a formula for the acceleration of an object of mass m on a frictionless surface w
    8·1 answer
  • A jar of tea is placed in sunlight until it reaches an equilibrium temperature of 31.8 ◦C . In an attempt to cool the liquid, wh
    6·1 answer
  • a cart is initially moving at 0.5 m/s along a track. The cart comes to rest after traveling I m. The experiment is repeated on t
    5·2 answers
  • A newly discovered planet has a radius twice as large as earth's and a mass five times as large. What is the free-fall accelerat
    7·1 answer
  • Quantitative data is _____________ Lesson 1.11
    9·1 answer
  • Leticia leaves the grocery store
    13·2 answers
  • (PLEASE HELP ILL GIVE OUT BRAINLIEST) Mr. Hicks stands on top of the roof and drops water ball oons at passing students. He miss
    15·2 answers
  • Are you going to finish that CROISSANT?
    7·2 answers
  • What role does gravity have in the motion of planets around the sun?
    13·1 answer
  • A merry-go-round rotates at the rate of 0.17 rev/s with an 79 kg man standing at a point 1.6 m from the axis of rotation.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!