To find if a series is either geometric or arithmetic:
it must satisfy this property:
Arithmetic:
a(n+1) - a(n) = const
Geometric:
a(n+1)/a(n) = const
In your case:
r1 = 7 -4 = 3
r2 = 12 - 7 = 5
r1 != r2 (not arirthmetic)
Geometric check:
r1 = 7/4
r2 = 12/7
r1 != r2 (not Geometric)
so neither.
Yes it is it is because So for a number to be divisible by 6, it must also be divisible by 2 and 3. Therefore, we need to check if a number is even and then check if the sum of the digits is divisible by 3.
<span>If 3 is added to the number: x + 3
b) ...and the sum is tripled..
"The sum" is "x + 3" so: 3(x+3)
c) ...the result is 27 more than the number.
27 more than the number is x + 27
d) Put it all together:
3(x + 3) = x + 27
Solve for x:
1) Distribute the left side of the equation:
3x + 9 = x + 27
2) Subtract x from each side of the equation:
2x + 9 = 27
3) Subtract 9 from each side of the equation:
2x = 18
4) Solve for x:
x = 9
Check:
1) x = 9
2) 3(x + 3) = x + 27
3) 3 ([9] + 3) = [9] + 27
4) 3(12) = 9 + 27
5) 36 = 36
So, therefore The answer is correct</span>
Answer:
the answer is 52.
Step-by-step explanation:
You have to do [(6+6+2)*(3)] + [(2)*(5)] to get your answer.
(6+6+2)=14
14*3=42
2*5=10
10+42=52
