Consider the function
, which has derivative
.
The linear approximation of
for some value
within a neighborhood of
is given by
Let
. Then
can be estimated to be
![\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B63.97%7D%5Capprox4-%5Cdfrac%7B0.03%7D%7B48%7D%3D3.999375)
Since
for
, it follows that
must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function
. This means the estimated value is an overestimation.
Indeed, the actual value is closer to the number 3.999374902...
Answer:
12r/t
Step-by-step explanation:
I think it would be 117
Because H is 63
So 90+90+63=243
360-243=117
I used 360 because angles in quadrilaterals add up to 360 degrees
100 notes were altogether
<em><u>Solution:</u></em>
Given that ratio of the number of $2 notes to the number of $5 notes was 4 : 1
number of $2 notes : number of $5 notes = 4 : 1
Let 4x be the number of $ 2 notes
Let 1x be the number of $ 5 notes
Given that total value of notes is $ 260
Therefore,
$ 2 (number of $ 2 notes ) + $ 5(number of $ 5 notes ) = $ 260
$ 2(4x) + $ 5(1x) = $ 260
8x + 5x = 260
13x = 260
x = 20
<em><u>Thus number of notes altogether is given as:</u></em>
4x + 1x = 4(20) + 1(20) = 80 + 20 = 100
Thus 100 notes were altogether
