The color of a star could give hints to mass temperature brightness density

Explain with equations and calculations, when necessary, whether an aqueous solution of each of these salts is acidic, basic, or

Julli [10]

NaHS is an acidic salt.

NaHS is obtained by replacement of one acidic hydrogen of `H2S` by Na (on reaction with NaOH).

<h3>What do we know about NaHS?</h3>

The chemical compound with the formula NaSH is sodium hydrosulfide. This substance is created when hydrogen sulfide is partially neutralized with sodium hydroxide. In the industrial setting, sodium sulfide and NaSH are frequently employed for the same things. Solid NaSH has no color.

Solution of sodium hydrosulfide is a colorless to light-yellow liquid. corrosive to flesh and metals. It is employed in the production of colors and paper pulp.

To learn more about acidic salt:

brainly.com/question/7178280

#SPJ4

7 0

1 year ago

A chemist prepares a solution of copper(II) fluoride by measuring out of copper(II) fluoride into a volumetric flask and filling

Simora [160]

The question is incomplete, here is the complete question.

A chemist prepares a solution of copper(II) fluoride by measuring out 0.0498 g of copper(II) fluoride into a 100.0mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to 3 significant digits.

Answer: The concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

Explanation:

To calculate the molarity of solute, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Given mass of copper (II) fluoride = 0.0498 g

Molar mass of copper (II) fluoride = 101.54 g/mol

Volume of solution = 100.0 mL

Putting values in above equation, we get:

$\text{Molarity of copper (II) fluoride)=\frac{0.0498\times 1000}{101.54\times 100.0}\\\\\text{Molarity of copper (II) fluoride}=4.90\times 10^{-3}mol/L$

Hence, the concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

4 0

2 years ago

Hey please answer this for me thanks.

Aleks [24]

Explanation:

Moles of N2 = 84/28 = 3.0mol

Moles of H2 = 29/2 = 14.5mol

Hence amount of ammonia produced = 6.0 * 17 = 102g.

7 0

2 years ago

Como clasificarias la máquina de la siguiente ilustración? tijera

Lina20 [59]

Answer:

máquina simple: palanca

Explanation:

En vista de que la pregunta está realizada en español, la respuesta la doy en el mismo lenguage.

La palanca es una máquina simple que consiste en una barra rígida que puede girar alrededor the un punto the pivote.

La forma en que functiona una palanca es que se aplica la ferza en el extremo de la barra que está más alejado del pivote. Este extremo puede desplazarse una larga distancia o arco, con una fuerza pequeña, haciendo que los puntos que están al otro lado del pivote, a una menor distancia de este, se desplacen una distancia o arco menor pero con más fuerza que la aplicada.

6 0

3 years ago

A hot air balloon is filled with 15 moles helium gas and 5 moles nitrogen gas. What is the volume of the balloon at 1.01 atm and

kvasek [131]

Given:

Moles of He = 15

Moles of N2 = 5

Pressure (P) = 1.01 atm

Temperature (T) = 300 K

To determine:

The volume (V) of the balloon

Explanation:

From the ideal gas law:

PV = nRT

where P = pressure of the gas

V = volume

n = number of moles of the gas

T = temperature

R = gas constant = 0.0821 L-atm/mol-K

In this case we have:-

n(total) = 15 + 5 = 20 moles

P = 1.01 atm and T = 300K

V = nRT/P = 20 moles * 0.0821 L-atm/mol-K * 300 K/1.01 atm = 487.7 L

Ans: Volume of the balloon is around 488 L

3 0

3 years ago