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ladessa [460]
3 years ago
10

The temperature of internal organs of a dead body and the environmental temperature at the scene of death are important to consi

der in determining _____.
Chemistry
1 answer:
12345 [234]3 years ago
5 0
The temperature of internal organs of a dead body and the environmental temperature at the scene of death are important to consider in determining the time of death.
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What is the average range of the PH scale?<br><br> THANKS!!
alex41 [277]
<span>The pH scale goes from 0-14. 0-6.9 is acidic, 7 is neutral and 7.1-14 is basic</span>
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3 years ago
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Car manufacturers are developing engines that use H₂ as fuel. In Iceland, Sweden, and other parts of Scandinavia, where hydroele
weeeeeb [17]

If the coulombs are supplied at 1.44 V, then 4.766 × 10¹¹ joules are produced.

(a) The reaction is

2H₂O + 2e⁻ → H₂ + 2OH⁻

According to the reaction, 2 moles of electrons flow per mole of reaction,

(b) Given

T = 25°C

Change Celsius into Kelvin

T = 25°C

   = (25 + 273 ) K

   = 298 K

<h3>What is Ideal Gas Law ?</h3>

It is expressed as

PV = nRT

Hence ,

n = \frac{PV}{RT}

   = \frac{(12)(3.5.10^{6} )}{(0.082057)(298)}

   = 1.7176 ×10⁶ mole

Now, From the given reaction we can say that ,1 mole of H₂  is produced by 2 moles of electron

Hence, 1.7176 × 10⁶ mole of H₂ is produced by

= 2 × 1.7176 × 10⁶ moles of  electron

= 3.435 ×10⁶ moles of electron

We know that

charge = moles of electron × F

          =  (3.435 ×10⁶ × 96500) C

           =  3.31 × 10¹¹ C

(c) We know that,

Voltage = \frac{energy}{charge}  =  \frac{J}{C}

1.44 V = \frac{energy}{3.31 . 10^{11} }

Energy = 1.44 V × 3.31 × 10¹¹ C

            =  4.766 × 10¹¹ Joules

Thus from the above conclusion we can say that, coulombs are supplied at 1.44 V, then 4.766 × 10¹¹ joules are produced.

Learn more about Fuel Cell here : brainly.com/question/16612142

#SPJ4

Disclaimer : The question given was incomplete on portal, Here is the complete question.

Question : Car manufacturers are developing engines that use H₂ as fuel. In Iceland, Sweden, and other parts of Scandinavia countries, where hydroelectric plants produce inexpensive electric power, the H₂ can be made industrially by the electrolysis of water.

a) How many moles of electrons flow per mole of reaction ?

b) How many coulombs are needed to produce 3.53X10⁶ L of H₂ gas at   12.0 atm and 25°C.

c) If the coulombs are supplied at 1.44 V, how many joules are produced?

8 0
2 years ago
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ale4655 [162]

What's your question? Am I missing something?

7 0
3 years ago
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2Fe(OH)3 Fe2O3+3H2O how many grams of Fe2O3 are produced if 10.7 grams of Fe (OH)3 react in this way
sasho [114]

Answer: 7.98 grams of Fe_2O_3 are produced if 10.7 grams of Fe(OH)_3 are reacted.

Explanation:

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)  

Putting values in equation 1, we get:

\text{Moles of} Fe(OH)_3=\frac{10.7g}{106.87g/mol}=0.100mol  

The chemical equation for the reaction is

2Fe(OH)_3\rightarrow Fe_2O_3+3H_2O

By Stoichiometry of the reaction:

2 moles of Fe(OH)_3 produce = 1 mole of Fe_2O_3

So, 0.100 moles of Fe(OH)_3 produce= \frac{1}{2}\times 0.100=0.05mol of Fe_2O_3  

Mass of Fe_2O_3 =moles\times {\text{Molar Mass}}=0.05mol\times 159.69g/mol=7.98g  

Hence 7.98 grams of Fe_2O_3 are produced if 10.7 grams of Fe(OH)_3 are reacted.

3 0
2 years ago
Convert 1.248×1010 g to each of the following units.
Leona [35]

Answer:

a) 1.248 x 10⁷ kg

b) 1.248 x 10⁴ Mg

c) 1.248 x 10¹³ mg

d) 1.248 x 10⁴ ton

Explanation:

a) Since 1000 g = 1 kg we can convert grams to kg by multiplyig any given quantity in grams by the conversion factor ( 1 kg / 1000 g):

1.248 x 10¹⁰ g * (1 kg / 1000 g) = 1.248 x 10⁷ kg

b) Since 1 Mg = 1 x 10⁶ g, the conversion factor will be ( 1 Mg / 1 x 10⁶ g):

1.248 x 10¹⁰ g * (  1 Mg / 1 x 10⁶ g) = 1.248 x 10⁴ Mg

c) Since 1 mg = 1 x 10⁻³ g, the conversion factor will be ( 1 mg / 1 x 10⁻³ g):

1.248 x 10¹⁰ g ( 1 mg / 1 x 10⁻³ g) = 1.248 x 10¹³ mg

d) Since 1 metric ton = 1000 kg and 1000 g = 1 kg, we can use these conversions factors: ( 1 kg / 1000 g) and (1 ton / 1000 kg):

1.248 x 10¹⁰ g * ( 1 kg / 1000 g) * ( 1 ton / 1000 kg) = 1.248 x 10⁴ ton

8 0
3 years ago
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