In this graph, what is the displacement of the particle in the last two seconds?

1 answer:

8 0

In this graph, what is the displacement of the particle in the last two seconds?of the particle in the last two seconds?

0.2 meters
2 meters
4 meters
6 meters
In this graph, the displacement of the particle in the last two seconds is 2 meters.

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Unpolarized light of intensity 0.0288 W/m2 is incident on a single polarizing sheet. What is the rms value of the electric field

galina1969 [7]

Answer:

the rms value of the electric field component transmitted is 3.295 V/m

Explanation:

Given;

intensity of the unpolarized light, I = 0.0288 W/m²

For unpolarized light, the relationship between the amplitude electric field and intensity is given as;

$E_{max} = \sqrt{2\mu_0cI} \\\\E_{max} = \sqrt{2(4\pi \times 10^{-7})(3\times 10^8)(0.0288)} \\\\E_{max} = 4.66 \ V/m$

The relationship between the rms value of the electric field and the amplitude electric field is given as;

$E_{rms} = \frac{E_0}{\sqrt{2} } =\frac{E_{max}}{\sqrt{2} } \\\\E_{rms} = \frac{4.66}{\sqrt{2} }\\\\E_{rms} = 3.295 \ V/m$

Therefore, the rms value of the electric field component transmitted is 3.295 V/m

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