The mass of the nuclide that will remain in the patient at 6:00 p.m. the next day is 94 g
<h3>How to determine the number of half-lives that has elapsed</h3>
We'll begin by obtaining the number of half lives that has elapsed. This can be obtained as follow:
- Half-life (t½) = 8 days = 8 × 24 = 192 hours
- Time (t) = 6 pm next day = 18 hours
- Number of half-lives (n) =?
n = t / t½
n = 18 / 192
n = 0.09375
<h3>How to determine the amount remaining </h3>
- Original amount (N₀) = 100 g
- Number of half-lives (n) = 0.09375
- Amount remaining (N) = ?
N = N₀ / 2^n
N = 100 / (2^0.09375)
N = 94 g
Thus, 94 g of the nuclide is remaining in the patient's body,
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Answer:
Mg(NO3)2 is the formula of manganese (IV) nitride.
Answer:
the answer is 0.4588162459
Explanation:
1 mole = 0.010195916576195
= 45 ×"
