A square current loop 4.9 cm on each side carries a 520 mA current. The loop is in a 1.0 T uniform magnetic field. The axis of t
he loop, perpendicular to the plane of the loop, is 30∘ away from the field direction.
What is the magnitude of the torque on the current loop? 2 sig fig.
What is the magnitude of the torque on the current loop? 2 sig fig.
2 answers:
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Answer:
30.7m
Explanation:
You can use the following equation:
ρ = R *
Where ρ is the resistivity, R is the resistance, S is the Cross-sectional Area and l is the length of the wire.
We issolate l in the equation and solve with the data we have:
l = R * = 3.25 Ω *
l = 30.7m