Answer:
3 m/s
Explanation:
Parameters given:
Mass of first bowling pin, m = 1.7 kg
Initial velocity of first bowling pin, u = 3.8 m/s
Final velocity of first bowling pin, v = 0.8 m/s
Mass of second bowling pin, M = 1.7 kg
Initial velocity of second bowling pin, U = 0 m/s
Let the final velocity of the second bowling pin be V
Using the principle of conservation of momentum:
Total initial momentum = Total final momentum
m*u + M*U = m*v + M*V
(1.7 * 3.8) + 0 = (1.7 * 0.8) + (1.7 * V)
6.46 = 1.36 + 1.7V
1.7V = 5.1
V = 5.1/1.7 = 3 m/s
Answer:
The correct option is d
Explanation:
From the question we are told that
The electric potential is 
The power is 
The charge delivered is 
Generally the power generated is mathematically represented as

=> 
=> 
=> 
This current flow is mathematically represented as

Where
is the charge delivered at t=0 s which is 0s
So



<span>Acceleration is the change in velocity divided by time taken. It has both magnitude and direction. In this problem, the change in velocity would first have to be calculated. Velocity is distance divided by time. Therefore, the velocity here would be 300 m divided by 22.4 seconds. This gives a velocity of 13.3928 m/s. Since acceleration is velocity divided by time, it would be 13.3928 divided by 22.4, giving a final solution of 0.598 m/s^2.</span>
We know, work done = Weight * Displacement
w = 3.76 * 2
w = 7.52 J
In short, Your Answer would be: 7.52 Joules
Hope this helps!
Answer:
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