Answer:
Explanation:
Given
Cross-sectional area of two areas is


It is filled with oil of density 
mass of car place on Large area 
Suppose a mass of m kg is placed on smaller area
According to pascal law's intensity of pressure is same at every point on Liquid




Answer
given,
F₁ is horizontal = 40 N
F₂ is normal = 20 N
F₃ is parallel = 30 N
work done by
W₂ = 0 as force is acting perpendicular to the direction of motion.
as the motion moved to 0.8 cm
W₃ = F₃ x d
W₃ = 30 x 0.8
W₃ = 24 J
W₁ = F₁ x d
W₁ = F₁ cos ∅ x d
W₁ = 40 cos 30⁰ x 0.8
W₁ = 27.21 J