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zzz [600]
3 years ago
10

Could a mixture be made up of only elements ?

Physics
1 answer:
USPshnik [31]3 years ago
3 0

Absolutely !  You're breathing a mixture like that right now.

Earth's atmosphere ... except for the small amounts of carbon dioxide
and water vapor ... is a mixture of gases in their elemental form.  A few
of them include nitrogen, oxygen, neon, argon, krypton.  All elements.

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sineoko [7]
Conduction i believe
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A wave travels with speed 200 m/s. Its wave number is 1.5 rad/m. What are its (a) wavelength and (b) frequency
Vladimir [108]

Answer:

(a)

Explanation:

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Kevin is a major stockholder in Professional Transmission Services (PTS), a nationwide network of transmission repair shops foun
const2013 [10]

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Kevin wants to make the firm private

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Based on the information provided within the question in regards to the situation it seems that Kevin wants to make the firm private. Private Firms are companies that are owned by non-governmental entities or instead owned by  a single individual or a very small amount of shareholders. Which is what Kevin seems to be wanting to do since he wants to buy back all the shares of the company so that only his family owns the company.

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3 years ago
Answer the question below. Use the rubric in the materials for help if needed. Use details to support your response.
butalik [34]

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5 0
4 years ago
Two point charges are on the y axis. A 3.90-µC charge is located at y = 1.25 cm, and a -2.4-µC charge is located at y = −1.80 cm
ladessa [460]

Answer:

a) 1.6*10^6 V

b) 13.35*10^6 V

Explanation:

The electric potential at origin is the sum of the contribution of the two charges. You use the following formula:

V=k\frac{q_1}{r_1}+k\frac{q_2}{r_2}    (1)

q1 = 3.90µC = 3.90*10^-6 C

q2 = -2.4µC = -2.4*10^-6 C

r1 = 1.25 cm = 0.0125 m

r2 = -1.80 cm = -0.018 m

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

You replace all the parameters in the equation (1):

V=k[\frac{q_1}{r_1}+\frac{q_2}{r_2}]\\\\V=(8.98*10^9Nm^2/C^2)[\frac{3.90*10^{-6}C}{0.0125m}+\frac{-2.4*10^{-6}C}{0.018m}]=1.6*10^6V

hence, the total electric potential is approximately 1.6*10^6 V

b) For the coordinate (1.50 cm , 0) = (0.015 m, 0) you have:

r1 = 0.0150m - 0.0125m = 0.0025m

r2= 0.015m + 0.018m = 0.033m

Then, you replace in the equation (1):

V=(8.98*10^9Nm^2/C^2)[\frac{3.90*10^{-6}C}{0.0025m}+\frac{-2.4*10^{-6}C}{0.033m}]=13.35*10^6V

hence, for y = 1.50cm you obtain V = 13.35*10^6 V

4 0
3 years ago
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