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Colt1911 [192]
3 years ago
10

If you increase the mass of an object, but keep the force on it constant, its acceleration decreases?

Physics
1 answer:
Damm [24]3 years ago
8 0
True, the acceleration will decrease if the mass in increased and the force remains constant.
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What are some ways scientists can study the seafloor?
TiliK225 [7]

Answer: A device records the time it takes sound waves to travel from the surface to the ocean floor and back again. Sound waves travel through water at a known speed. Once scientists know the travel time of the wave, they can calculate the distance to the ocean floor.

Explanation:

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The competitive exclusion principle states that _______.
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<span>The competitive exclusion principle states that when two organisms attempt to fill the same niche, one will exclude the other from the ecosystem. Research partitioning is an adaptive evolution that when species are have similar preys, they compete with each other and one species is deemed to extinct in the process however if two species are of different preys, then they can exist with one another. To exist with one another, organisms belonging to a same species either compete for the resources or divide it amongst themselves. This concept is important because it helps in diversified ecology, where animals and plants of the same species co-exist and creates a beauty with nature.</span>
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A ball is hit 1 meter above the ground with an initial speed of 40 m/s. If the ball is hit at an angle of 30 above the horizonta
Vika [28.1K]

Answer:

t_t=4.131\ s

Explanation:

Given:

height above the horizontal form where the ball is hit, y=1\ m

angle of projectile above the horizontal, \theta=30^{\circ}

initial speed of the projectile, u=40\ m.s^{-1}

<u>Firstly we find the </u><u>vertical component of the initial velocity</u><u>:</u>

u_y=u.\sin\theta

u_y=40\times \sin30^{\circ}

u_y=20\ m.s^{-1}

During the course of ascend in height of the ball when it reaches the maximum height then its vertical component of the velocity becomes zero.

So final vertical velocity during the course of ascend:

  • v_y=0\ m.s^{-1}

Using eq. of motion:

v_y^2=u_y^2-2g.h (-ve sign means that the direction of velocity is opposite to the direction of acceleration)

0^2=20^2-2\times 9.8\times h

h=20.4082\ m (from the height where it is thrown)

<u>Now we find the time taken to ascend to this height:</u>

v_y=u_y-g.t

0=20-9.8t

t=2.041\ s

<u>Time taken to descent the total height:</u>

  • we've total height, h'=h+y =20.4082+1

h'=u_y'.t'+\frac{1}{2} g.t'^2

  • during the course of descend its initial vertical velocity is zero because it is at the top height, so u_y'=0\ m.s^{-1}

21.4082=0+4.9t'^2

t'=2.09\ s

<u>Now the total time taken by the ball to hit the ground:</u>

t_t=t'+t

t_t=2.09+2.041

t_t=4.131\ s

3 0
3 years ago
*example of previous incorrect/correct answer on similar question) Inside a vacuum tube, an electron is in the presence of a uni
andrezito [222]

The final speed of the electron is 4.64 * 10^5 m/s.

<h3>What is the speed of the electron?</h3>

Given that the mass of the electron is obtained as 9.11 * 10^-31 Kg, we have that the charge of the electron is 1.6 * 10^-19 C.

E= F/q

F = Eq

F =  330 N/C * 1.6 * 10^-19 C

F = 5.28 * 10^-17 N

F = ma

a = F/m = 5.28 * 10^-17 N/ 9.11 * 10^-31 Kg

a = 5.8 * 10^13 m/s^2

Using

v = u + at

u = 0 m/s because the electron was initially at rest

v = at

v = 5.8 * 10^13 * 8.00 ✕ 10−⁹ s

v = 4.64 * 10^5 m/s

Learn more about the speed of the electron:brainly.com/question/13130380

#SPJ1

8 0
2 years ago
Calculate the potential difference if 80J of energy are transferred by 20C of charge.
olga_2 [115]
Using the equation:

Energy transferred = Charge x Potential difference

Rearrange for p.d:

V = E/Q

Substitute values:

V = 80/20

V = 4
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