Let u = the vertical launch speed.
Neglect air resistance, and g = 9.8 m/s².
At the maximum height of h = 120 cm = 1.2 m, the vertical velocity is zero.
Therefore
(u m/s)² - 2*(9.8 m/s²)*(1.2 m) = 0
u² = 23.52 (m/s)²
u = 4.85 m/s
The time to attain maximum height is one half of the travel time.
If t = time to attain maximum height, then
u - gt = 0
4.85 - 9.8t = 0
t = 4.85/9.8 = 0.495 s
Therefore the travel time is 2*0.0495 = 0.99 s
Answers:
(a) 4.85 m/s
(b) 0.99 s
To develop this problem it is necessary to apply the concepts related to Broglie hypothesis.
The hypothesis defines that
Where,
P = momentum
h = Planck's constant
The momentum is also defined as,
P = mv
Where,
m = mass
v = Velocity
PART A) Replacing at the first equation
Our values are given as,
Re-arrange to find v, we have:
PART B) From the kinematic equations of movement description we know that velocity is defined as displacement over a period of time, that is
Re-arrange to find t,
the age of the universe.
Answer:
i dont really nnow the answer so byee
Answer
given,
mass of the boiled egg = 50 g = 0.05 Kg
spring constant, k = 25 N/m
initial Amplitude, A₁ = 0.3 m
final amplitude, A₂ = 0.1 m
time, t = 5 s
considering the amplitude of damped harmonic oscillation to calculate damping factor.
b is the damping factor and t is the time.
on solving
inserting all the given values
b = 0.0219 Kg/s
damping coefficient in three significant figure
b = 0.022 Kg/s