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3 years ago

10

Which has more gravitaatoinal potental energy: a bird on the ground or the same bird in the tree? why?

1 answer:

julsineya [31]3 years ago

7 0

The same bird on the tree has more gravitational potential energy. This is because it is at a higher distance from the ground as it is on the tree, than when it is on the ground.

Considering also the formula for Gravitational Potential Energy GPE = mgh

For the bird on the ground, h =0, therefore GPE = m*9.8*0 = 0

For that on the tree = mgh = m*9.8*h

Of course the one on the tree has a value greater than zero.

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4 years ago

State a true conclusion.

Ganezh [65]

The conclusion is; Cathy's dad has gone fishing.

<h3>What are conclusions in conditional statements?</h3>

A conditional statement is a statement with a hypothesis which is then followed by a conclusion.

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The hypothesis is “if,” part of a conditional statement.

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7 0

2 years ago

A proton is released from rest at the origin in a uniform electric field that is directed in the positive xx direction with magn

elena-s [515]

Answer:

The change in potential energy is $\Delta PE = - 3.8*10^{-16} \ J$

Explanation:

From the question we are told that

The magnitude of the uniform electric field is $E = 950 \ N/C$

The distance traveled by the electron is $x = 2.50 \ m$

Generally the force on this electron is mathematically represented as

$F = qE$

Where F is the force and q is the charge on the electron which is a constant value of $q = 1.60*10^{-19} \ C$

Thus

$F = 950 * 1.60 **10^{-19}$

$F = 1.52 *10^{-16} \ N$

Generally the work energy theorem can be mathematically represented as

$W = \Delta KE$

Where W is the workdone on the electron by the Electric field and $\Delta KE$ is the change in kinetic energy

Also workdone on the electron can also be represented as

$W = F* x *cos( \theta )$

Where $\theta = 0 ^o$ considering that the movement of the electron is along the x-axis

So

$\Delta KE = F * x cos (0)$

substituting values

$\Delta KE = 1.52 *10^{-16} * 2.50 cos (0)$

$\Delta KE = 3.8*10^{-16} J$

Now From the law of energy conservation

$\Delta PE = - \Delta KE$

Where $\Delta PE$ is the change in potential energy

Thus

$\Delta PE = - 3.8*10^{-16} \ J$

7 0

3 years ago