Answer:
Electric potential = 0.00054 V
Explanation:
We are given;
Charge; q = 3 pC = 3 × 10^(-12) C
Radius; r = 2 cm = 0.02 m
Formula for the electric potential of this surface will be;
V = kqr
Where;
K is a constant = 9 × 10^(9) N⋅m²/C².
Thus;
V = 9 × 10^(9) × 3 × 10^(-12) × 0.02
V = 0.00054 V
The reasoning for this is false
Answer:
Explanation:
False --> A cylindrical capacitor is essentially a parallel plate capacitor rolled into a tube. This is because a cylindrical capacitor comprises two cylinders.
False --> The dielectric constant indicates the distance by which the two plates of a capacitor are separated.
True --> The charge on a capacitor increases quickly at first, then much more slowly as the capacitor charges. This is because the charge on the capacitor increases exponentially.
False --> The voltage across a capacitor in an RC circuit increases linearly during charging. This is because the voltage increases exponentially.
True --> One of the principal purposes of a capacitor is to store electric potential energy.
True --> A capacitor charges rapidly when connected to an RC circuit with a battery. This is because a cylindrical capacitor is basically a parallel plate capacitor rolled into a tube.
Answer:10 A
Explanation:
According to the KCL (Kirchhoff's current laws)
The correct answer is B .
Electrically charged particles.