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lawyer [7]
1 year ago
6

*example of previous incorrect/correct answer on similar question) Inside a vacuum tube, an electron is in the presence of a uni

form electric field with a magnitude of 330 N/C.
(a) What is the magnitude of the acceleration of the electron (in m/s²)?
__________m/s²

(b) The electron is initially at rest. What is its speed (in m/s) after 8.00 ✕ 10−⁹ s?
______m/s

Physics
1 answer:
andrezito [222]1 year ago
8 0

The final speed of the electron is 4.64 * 10^5 m/s.

<h3>What is the speed of the electron?</h3>

Given that the mass of the electron is obtained as 9.11 * 10^-31 Kg, we have that the charge of the electron is 1.6 * 10^-19 C.

E= F/q

F = Eq

F =  330 N/C * 1.6 * 10^-19 C

F = 5.28 * 10^-17 N

F = ma

a = F/m = 5.28 * 10^-17 N/ 9.11 * 10^-31 Kg

a = 5.8 * 10^13 m/s^2

Using

v = u + at

u = 0 m/s because the electron was initially at rest

v = at

v = 5.8 * 10^13 * 8.00 ✕ 10−⁹ s

v = 4.64 * 10^5 m/s

Learn more about the speed of the electron:brainly.com/question/13130380

#SPJ1

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If the mass of the block is 5 kg and the speed 7 m/s, what is the work done <br> on the block?
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Answer:

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Coeffecient of friction=0.2

external applied force, F=40N

The angle at which the force is applied=30degree

So the horizontal component of force=Fcos30=40×

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While the uertical component of the force acting in upward direction=Fsin30=40× 21

​ =20N

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​

N−6N=28.64N

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A uniform electric field exists in the region between two oppositely charged plane parallel plates. a proton is released from re
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where

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