Answer:
Both warming up and cooling down or not important
Explanation:
The first attachment contains the complete question while the second attachment is the solution.
For the answer to the question above,
<span>Q = amount of heat (kJ) </span>
<span>cp = specific heat capacity (kJ/kg.K) = 4.187 kJ/kgK </span>
<span>m = mass (kg) </span>
<span>dT = temperature difference between hot and cold side (K). Note: dt in °C = dt in Kelvin </span>
<span>Q = 100kg * (4.187 kJ/kgK) * 15 K </span>
<span>Q = 6,280.5 KJ = 6,280,500 J = 1,501,075.5 cal</span>
Answer: -1.27 m/s^2
Explanation:
a = - V^2 / 2x
a = -(25^2) / 2 x (246) = 1.27 m/ s^2
Therefore the linear acceleration of the wheel is - 1.27 m/s^2