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3 years ago

A circuit is built based on the circuit diagram shown.

Physics

2 answers:

notka56 [123]3 years ago

5 0

Answer:

The correct answer is A

Explanation:

The diagram provided is that of resistors connected in parallel since each individual resistor is directly connected to the 60 V voltage source.

In order to calculate the resistor's current (in amphere, A) in the 50 Ω resistor, the resistor's voltage (in volts,V) is divided by the resistance (in ohms, Ω).

Hence,

Current = voltage ÷ resistance

The voltage is provided in the diagram to be 60 V

Current = 60 ÷ 50

Current = 1.2 A

julsineya [31]3 years ago

4 0

The current in the 50 Ω resistor is A) 1.2 A

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7. 13 a turbine receives steam at 6 mpa, 600°c with an exit pressure of 600 kpa. Assume the turbine is adiabatic and neglect kin

AnnyKZ [126]

The work done by the turbine will be 708.2 kJ/kg. The work done by the turbine is the difference of the enthalpy at inlet and exit.

<h3 /><h3>What is temperature?</h3>

Temperature directs the hotness or coldness of a body. In clear terms, it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles, more the temperature.

If the given turbine is assumed to be reversible;

$\rm P_I$ (Initial pressure)=60 mpa = 60 bar

$\rm T_i$ (Initial temperature)=600° C

$\rm P_e$ (Exit pressure)=600 kpa=6 bar

The heat balance equation is;

$\rm q-W_t=h_e-h_i\\\\ q=0\\\\\ W_t=h_i-h_e$

The change in the entropy is;

$\rm S_2-S_1=\frac{\delta q}{dt}$

The work done by the turbine is;

$\rm W_t = h_i-h_e\\\\ W_t =3658.4 -29.5019\\\\ W_t =708.2 \ kJ/kg$

Hence,the work done by the turbine will be 708.2 kJ/kg.

To learn more about the temperature, refer to the link;

brainly.com/question/7510619

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6 0

2 years ago

Car B has the same mass as Car A but is going twice as fast. If the same constant force brings both cars to a stop, how far will

evablogger [386]

Answer:four times

Explanation:

Given

mass of both cars A and B are same suppose m

but velocity of car B is same as of car A

Suppose velocity of car A is u

Velocity of car B is 2 u

A constant force is applied on both the cars such that they come to rest by travelling certain distance

using to find the distance traveled

where, v=final velocity

u=initial velocity

a=acceleration(offered by force)

s=displacement

final velocity is zero

For car A

$0-(u)^2=2\times a\times s$

$s_a=\frac{u^2}{2a}------1$

For car B

$0-(2u)^2=2\times a\times s_b$

$s_b=\frac{4u^2}{2a}----2$

divide 1 and 2 we get

$\frac{s_a}{s_b}=\frac{1}{4}$

thus $s_b=4\cdot s_a$

distance traveled by car B is four time of car A

7 0

3 years ago

You could use an elevator or the stairs to lift a box to tenth floor.which has greater power?

erastova [34]

Stairs don't have any power at all. All the energy used to climb them
has to come from your muscles.

An elevator gets its power from the electric motors that lift it. All YOU
have to do is stand there and look around.

All of this is a big part of the reason why elevators have become so
popular, and why no buildings with more than a few floors were built
before elevators were invented.

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3 years ago

A student practicing for a cross country meet runs 250 m in 30 s. What is the average speed

Kaylis [27]

Answer:8.3m/sec 30 sec,

Explanation:

A student practicing for a track meet, ran 250 m in 30 sec. a. What was her average speed? 250 m = 8.3 m/sec 30 sec.

5 0

2 years ago

Read 2 more answers

#1 Not sure where to start. This is for AP Physics!

yaroslaw [1]

First,

$\rho=\dfrac mV$

where $\rho$ is density, $m$ is mass, and $V$ is volume. We can compute the volume of the roll:

$2.7\,\dfrac{\mathrm g}{\mathrm{cm}^3}=\dfrac{1275\,\mathrm g}V$

$\implies V\approx472.22\,\mathrm{cm}^3\approx4.72\,\mathrm m^3$

When the roll is unfurled, the aluminum will be a rectangular box (a very thin one), so its volume will be the product of the given area and its thickness $x$ . Note that we're assuming the given area is not the actual total surface area of the aluminum box, but just the area of the largest face (i.e. the area of one side of the unrolled sheet of aluminum).

So we have

$V=Ax$

where $A$ is the given area, so

$4.72\,\mathrm m^3=\left(18.5\,\mathrm m^2\right)x$

$\implies x\approx0.255\,\mathrm m=255\,\mathrm{mm}$

If we're taking significant digits into account, the volume we found would have been $V=470\,\mathrm m^3$ , in turn making the thickness $x=250\,\mathrm{mm}$ .

8 0

3 years ago