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miss Akunina [59]
3 years ago
7

Consider a system consisting of two Einstein solids, A and B, each containing N= 10 oscillators, and sharing a total of q= 20 un

its of energy. Assume that the two solids areweakly coupled and the total energy is fixed.
Required:
a. How many different macrostates are available to solid A or B?
b. How many different microstates are available to the combined system of A & B?
c. Starting with the exact form for the multiplicity of an Einstein solid, calculate the probability of finding all the energy in solid A, assuming that the system is in thermal equilibrium.
d. Calculate the probability of finding exactly half the energy in solid A.
Physics
1 answer:
Daniel [21]3 years ago
7 0

Answer:Gg

Explanation:

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luda_lava [24]

(a) Away from the normal

We can find the direction of bending of the ray of light by using Snell's equation:

n_1 sin \theta_1 = n_2 sin \theta_2

where we have:

n1, n2: index of refraction of the first and second medium

\theta_1, \theta_2; angle that the incident and the refracted ray form with the normal to the surface

Here, the light ray moves from a material with high index of refraction to a material with lower index, so we have

n_1 > n_2

Re-arranging Snell's law we find

sin \theta_2 = \frac{n_1}{n_2} sin \theta_1

since we have

\frac{n_1}{n_2}>1

this implies

sin \theta_2 > sin \theta_1\\\theta_2 > \theta_1

so the ray of light bends away from the normal.

(b) The wavelength is greater in the second material (the one with lower index of refraction)

The wavelength of the light in a medium is given by

\lambda=\frac{\lambda_0}{n}

where

\lambda_0 is the wavelength of the light in a vacuum

n is the refractive index

The equation can be rewritten as

\lambda_0 = \lambda_1 n_1 = \lambda_2 n_2

and again it can be rewritten as

\lambda_2 = \frac{n_1}{n_2} \lambda_1

where

\lambda_1 = 600 nm\\\frac{n_1}{n_2}>1

Therefore, we have that the wavelength in the second medium (the one with lower index of refraction) is longer than the wavelength in the first medium.

(c) The frequency remains the same

Wavelength and speed of a light ray depend on the medium in which the wave is travelling through, however the frequency does not depend on that, so it remains the same in the two mediums.

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3 years ago
Yellow light with wavelength 600 nm is travelling to the left (in the negative x direction) in vacuum. The light is polarized al
kiruha [24]

Answer: (a) and (b) => check attached file.

(c). Picture (a) and (b) will both remain the same.

Explanation:

IMPORTANT: The solution to the question (a) and (b) that is  (a) Draw a neat snapshot mode labeled vector picture of the wave. (b) Draw a neat movie mode labeled vector picture of the wave is there in the ATTACHED FILE/PICTURE.

It is also worthy of note to know that in anything Electromagnetic wave, the magnetic field, the Electric Field and their direction of propagation are perpendicular to each other.

Therefore, knowing the fact above we can say that in yellow light, the magnetic field is in the y-direction and the Electric Field is in the z-direction.

Hence, the solution to option C is given below;

(C).If the wave were to represent blue light instead of yellow light, picture (a) will remain the same because both light are Electromagnetic wave, although the wavelength will have to change. Picture (b) will also remain the same because they are both Electromagnetic waves and possess similar properties.

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4 years ago
Newtons _ law of motion states that every action has an equal and opposite reaction​
vlada-n [284]

Answer:

3rd

Explanation:

3rd

6 0
3 years ago
Integrated Science- 8th grade science
padilas [110]

Answer:

A. a rigorously tested explanation

Explanation:

  • B. and D. are out - theories are not opinionated, they are factual
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3 0
3 years ago
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What is the magnitude of the minimum magnetic field that will keep the particle moving in the earth's gravitational field in the
Zepler [3.9K]

Answer:

The magnitude of the magnetic field vector is 1.91T and is directed towards the east.

The steps to the solution can be found in the attachment below.

Explanation:

For the charge to remain in the the earth' gravitational field the magnetic force on the charge must be equal to the earth's gravitational force on the charge and must act opposite the direction of the earth's gravitational force.

Fm = Fg

qvBSin(theta) = mg

Where q = magnitude of charge

v = magnitude of the velocity vector = 4 x10^4 m/s

B = magnitude of the magnetic field vector

theta = the angle between the magnetic field and velocity vectors = 90°

m = mass of the charge = 0.195g

g = acceleration due to gravity =9.8m/s²

On substituting the respective values of all variables in the equation (1) above

B = 1.91T

The direction of the magnetic field vector was found by the application of the right hand rule: if the thumb is pointed in the direction of the magnetic force and the index finger is pointed in the direction of the velocity vector, the middle finger points in the direction of the magnetic field.

Below is the step by step procedure to the solution.

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