All categories

3 years ago

Which compound has both ionic and covalent bonding?

Chemistry

2 answers:

irina1246 [14]3 years ago

8 0

The compound that has both ionic and covalent bonding is $\boxed{\left( 1 \right){\text{ CaC}}{{\text{O}}_3}}$ .

Further Explanation:

The attraction between different atoms, molecules and ions is known as a chemical bond. The formation of various types of compounds takes place as a result of these chemical bonds.

An ionic bond is formed as a result of the interaction between a metal and a non-metal. Metals have the tendency to lose electrons while non-metals tend to gain electrons. Due to this, metal atoms form cations by loss of electrons and non-metals become anions with the gain of electrons.

A covalent bond is formed by the mutual sharing of electrons between the bonded atoms. It is also called the molecular bond. Such bonds usually exist between two or more non-metals.

(1) ${\text{CaC}}{{\text{O}}_{\text{3}}}$

Its constituents are ${\text{C}}{{\text{a}}^{2 + }}$ and ${\text{CO}}_3^{2 - }$ ions. The bond between calcium and carbonate ions is an ionic bond. But the bond between the carbon atom and the oxygen atom of carbonate is formed by sharing of electrons so it is a covalent bond. So ${\text{CaC}}{{\text{O}}_{\text{3}}}$ has both ionic and covalent bonding and therefore this option is correct.

(2) ${\text{C}}{{\text{H}}_2}{\text{C}}{{\text{l}}_2}$

It has carbon, hydrogen and chlorine atoms. All of them are nonmetals and the bonds formed between nonmetals are covalent bonds. So ${\text{C}}{{\text{H}}_2}{\text{C}}{{\text{l}}_2}$ has only covalent bonds and therefore this option is incorrect.

(3) ${\text{C}}{{\text{H}}_3}{\text{OH}}$

It has carbon, hydrogen and oxygen atoms. All of them are nonmetals and the bonds formed between nonmetals are covalent bonds. So ${\text{C}}{{\text{H}}_3}{\text{OH}}$ has only covalent bonds and therefore this option is incorrect.

(4) ${{\text{C}}_{\text{6}}}{{\text{H}}_{{\text{12}}}}{{\text{O}}_{\text{6}}}$

It has carbon, hydrogen and oxygen atoms. All of them are nonmetals and the bonds formed between nonmetals are covalent bonds. So ${{\text{C}}_{\text{6}}}{{\text{H}}_{{\text{12}}}}{{\text{O}}_{\text{6}}}$ has only covalent bonds and therefore this option is incorrect.

Learn more:

Identification of ionic bonding: brainly.com/question/1603987
What type of bond exists between phosphorus and chlorine? brainly.com/question/81715

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Ionic and covalent compounds

Keywords: chemical bond, ionic bond, covalent bond, CaCO3, CH2Cl2, C2H12O6, CH3OH, carbon, hydrogen, oxygen.

Zielflug [23.3K]3 years ago

6 0

(1) CaCO3 is the correct answer.

The type of bond formed between Ca2+ and CO3 2- is ionic, and the type of bond formed between C and O is covalent.

Hope this helps~

You might be interested in

With what compound will nh3 experience only dispersion intermolecular forces? with what compound will nh3 experience only disper

Burka [1]

Answer is: ammonia experience only dispersion intermolecular forces with BF₃ (boron trifluoride) because BF₃ is only nonpolar molecule (vectors of dipole moments cansel each other, dipole moment is zero).
The London dispersion force (intermolecular force) is a temporary attractive force between molecules.

6 0

3 years ago

Read 2 more answers

What is C6H5 called?

zysi [14]

C6H5 is the molecular formula for Phenyl.

5 0

3 years ago

Read 2 more answers

Which describes a stationary reference point?

kondaur [170]

Answer: C

Explanation:

7 0

3 years ago

Calculate the activity coefficients for the following conditions:

uysha [10]

Answer:

For a: The activity coefficient of copper ions is 0.676

For b: The activity coefficient of potassium ions is 0.851

For c: The activity coefficient of potassium ions is 0.794

Explanation:

To calculate the activity coefficient of an ion, we use the equation given by Debye and Huckel, which is:

$-\log\gamma_i=\frac{0.51\times Z_i^2\times \sqrt{\mu}}{1+(3.3\times \alpha _i\times \sqrt{\mu})}$ ........(1)

where,

$\gamma_i$ = activity coefficient of ion

$Z_i$ = charge of the ion

$\mu$ = ionic strength of solution

$\alpha _i$ = diameter of the ion in nm

To calculate the ionic strength, we use the equation:

$\mu=\frac{1}{2}\sum_{i=1}^n(C_iZ_i^2)$ ......(2)

where,

$C_i$ = concentration of i-th ions

$Z_i$ = charge of i-th ions

For a:

We are given:

0.01 M NaCl solution:

Calculating the ionic strength by using equation 2:

$C_{Na^+}=0.01M\\Z_{Na^+}=+1\\C_{Cl^-}=0.01M\\Z_{Cl^-}=-1$

Putting values in equation 2, we get:

$\mu=\frac{1}{2}[(0.01\times (+1)^2)+(0.01\times (-1)^2)]\\\\\mu=0.01M$

Now, calculating the activity coefficient of $Cu^{2+}$ ion in the solution by using equation 1:

$Z_{Cu^{2+}}=2+\\\alpha_{Cu^{2+}}=0.6\text{ (known)}\\\mu=0.01M$

Putting values in equation 1, we get:

$-\log\gamma_{Cu^{2+}}=\frac{0.51\times (+2)^2\times \sqrt{0.01}}{1+(3.3\times 0.6\times \sqrt{0.01})}\\\\-\log\gamma_{Cu^{2+}}=0.17\\\\\gamma_{Cu^{2+}}=10^{-0.17}\\\\\gamma_{Cu^{2+}}=0.676$

Hence, the activity coefficient of copper ions is 0.676

For b:

We are given:

0.025 M HCl solution:

Calculating the ionic strength by using equation 2:

$C_{H^+}=0.025M\\Z_{H^+}=+1\\C_{Cl^-}=0.025M\\Z_{Cl^-}=-1$

Putting values in equation 2, we get:

$\mu=\frac{1}{2}[(0.025\times (+1)^2)+(0.025\times (-1)^2)]\\\\\mu=0.025M$

Now, calculating the activity coefficient of $K^{+}$ ion in the solution by using equation 1:

$Z_{K^{+}}=+1\\\alpha_{K^{+}}=0.3\text{ (known)}\\\mu=0.025M$

Putting values in equation 1, we get:

$-\log\gamma_{K^{+}}=\frac{0.51\times (+1)^2\times \sqrt{0.025}}{1+(3.3\times 0.3\times \sqrt{0.025})}\\\\-\log\gamma_{K^{+}}=0.070\\\\\gamma_{K^{+}}=10^{-0.070}\\\\\gamma_{K^{+}}=0.851$

Hence, the activity coefficient of potassium ions is 0.851

For c:

We are given:

0.02 M $K_2SO_4$ solution:

Calculating the ionic strength by using equation 2:

$C_{K^+}=(2\times 0.02)=0.04M\\Z_{K^+}=+1\\C_{SO_4^{2-}}=0.02M\\Z_{SO_4^{2-}}=-2$

Putting values in equation 2, we get:

$\mu=\frac{1}{2}[(0.04\times (+1)^2)+(0.02\times (-2)^2)]\\\\\mu=0.06M$

Now, calculating the activity coefficient of $K^{+}$ ion in the solution by using equation 1:

$Z_{K^{+}}=+1\\\alpha_{K^{+}}=0.3\text{ (known)}\\\mu=0.06M$

Putting values in equation 1, we get:

$-\log\gamma_{K^{+}}=\frac{0.51\times (+1)^2\times \sqrt{0.06}}{1+(3.3\times 0.3\times \sqrt{0.06})}\\\\-\log\gamma_{K^{+}}=0.1\\\\\gamma_{K^{+}}=10^{-0.1}\\\\\gamma_{K^{+}}=0.794$

Hence, the activity coefficient of potassium ions is 0.794

6 0

3 years ago

Which two from this group have an identical number of energy levels?

storchak [24]

Answer: C

Explanation: Took the test

5 0

3 years ago