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goldenfox [79]
3 years ago
13

Discuss: Reaction-Rate Factors

Chemistry
1 answer:
SpyIntel [72]3 years ago
3 0
1) The time depends on what the lab wanted you to do.  It will tell you in the procedure when you are supposed to considered a reaction to be complete and you just measure the time for that to happen.

2) Most text books say that increasing the concentration of one or more reactants will increase the rate of the reaction.  To prove this with your data you need to show that when you increased the concentration of one of the reactants, the reaction rate did increase.  The results of this experiment are not enough to make a general statement since the experiment was not on a large enough scale to diffidently prove anything.  (you could have been testing the one exception or had a error in one of your trials)
I hope this helps.  Let me know in the comments if anything is unclear.

(The concentration of one or more of the reactants will increase the rate of the reaction.  This is explained through the fact that all reactions require collisions that have certain orientations and a minimum energy level.  By increasing the concentration of one or more reactants, you   increase the number of collisions which increases the rate since requires collisions in order to occur.)  <span />
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(4Ga + 3S2 → 2Ga2S3)
nexus9112 [7]

Answer:

n_S=1.076molS

Explanation:

Hello,

In this case, given the undergoing chemical reaction, we can see a 4:3 mole ratio between the consumed moles of gallium and sulfur respectively, therefore, the consumed moles of sulfur, from the 100.0 g of gallium (use its atomic mass) turn out:

n_{S}=100.0gGa*\frac{1molGa}{69.72gGa}*\frac{3molS}{4molS}  \\\\n_S=1.076molS

Best regards.

7 0
3 years ago
If a large chunk of sulfur is ground into powder, its mass will ___
pochemuha
Its mass will stay the same
8 0
3 years ago
Substances that absorb energy in the form of heat are
Yanka [14]

Answer:

Substances that absorb energy in the form of heat are

b)endothermic.

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7 0
3 years ago
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When heated, calcium carbonate decomposes according to the equation given below:
Margaret [11]

Answer:

Percent yield = 90.9%

Explanation:

Given data:

Mass of CaCO₃ = 50.0 g

Mass of CO₂ produced = 20.0 g

Percent yield = ?

Solution:

Chemical equation:

CaCO₃ →  CaO + CO₂

Number of moles of CaCO₃:

Number of moles = mass/molar mass

Number of moles = 50.0 g/ 100.1 g/mol

Number of moles = 0.5 mol

Now we will compare the moles of CO₂ with CaCO₃.

                      CaCO₃          :        CO₂

                          1                :           1

                       0.5               :          0.5

Mass of CO₂: Theoretical yield

Mass = number of moles × molar mass

Mass = 0.5 mol × 44 g/mol

Mass = 22 g

Percent yield:

Percent yield = ( actual yield / theoretical yield ) × 100

Percent yield = (20.0 g/ 22.0 g) × 100

Percent yield = 0.909 × 100

Percent yield = 90.9%

5 0
3 years ago
Look at the reaction below.
HACTEHA [7]
The acid is H2SO4(an)
6 0
3 years ago
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