Answer:
1.heat a pan of water with just a little bit of water,have a boil
2.chosse ure salt
3.stir in has much salt has u can than take the pan off the heat
4.pour the mix into a glass jar
5.tie a string to an objeet that can lay accross the top and put just the string in ure mix
Explanation oh and look at it everyday hope that helps
Energy were released from the walnut, q = 1,673.6 J
<h3>Equation :</h3>
To find the energy using formula,
q = mcΔt
where,
q is charge
m is mass
c is specific heat of water
Δt is change in temperature
So, given
t₁ = 50°C
t₂ = 60°C
m = 40g
c = 4.184 J/g
Now putting the values known,
We get,
q = mc(t₂ - t₁)
q = 40g x 4.184 J/g x (60 - 50)
q = 167.36 J x 10
q = 1,673.6 J
<h3>What is heat energy?</h3>
Heat is the thermal energy that is transferred when two systems with different surface temperatures come into contact. Heat is denoted by the letters q or Q and is measured in Joules.
To know more about specific heat :
brainly.com/question/11297584
#SPJ9
Answer:
ITS FALSE electricity doesn't travel through wood same with cement!
Answer:
ΔS° = -268.13 J/K
Explanation:
Let's consider the following balanced equation.
3 NO₂(g) + H₂O(l) → 2 HNO₃(l) + NO(g)
We can calculate the standard entropy change of a reaction (ΔS°) using the following expression:
ΔS° = ∑np.Sp° - ∑nr.Sr°
where,
ni are the moles of reactants and products
Si are the standard molar entropies of reactants and products
ΔS° = [2 mol × S°(HNO₃(l)) + 1 mol × S°(NO(g))] - [3 mol × S°(NO₂(g)) + 1 mol × S°(H₂O(l))]
ΔS° = [2 mol × 155.6 J/K.mol + 1 mol × 210.76 J/K.mol] - [3 mol × 240.06 J/K.mol + 1 mol × 69.91 J/k.mol]
ΔS° = -268.13 J/K
<span>Mass=25.7gm
dimensions,
l=2.3cm
b=4.01cm
h=1.82cm
Thus,Density=Mass/Volume=m/lbh=25.7/2.3*4.01*1.82 g cm-3</span>
