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goldenfox [79]
3 years ago
13

Discuss: Reaction-Rate Factors

Chemistry
1 answer:
SpyIntel [72]3 years ago
3 0
1) The time depends on what the lab wanted you to do.  It will tell you in the procedure when you are supposed to considered a reaction to be complete and you just measure the time for that to happen.

2) Most text books say that increasing the concentration of one or more reactants will increase the rate of the reaction.  To prove this with your data you need to show that when you increased the concentration of one of the reactants, the reaction rate did increase.  The results of this experiment are not enough to make a general statement since the experiment was not on a large enough scale to diffidently prove anything.  (you could have been testing the one exception or had a error in one of your trials)
I hope this helps.  Let me know in the comments if anything is unclear.

(The concentration of one or more of the reactants will increase the rate of the reaction.  This is explained through the fact that all reactions require collisions that have certain orientations and a minimum energy level.  By increasing the concentration of one or more reactants, you   increase the number of collisions which increases the rate since requires collisions in order to occur.)  <span />
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Geologists have a rule of thumb: when molten rock cools and solidifies, crystals of compounds with the smallest lattice energies
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Geologists have a rule of thumb: when molten rock cools and solidifies, crystals of compounds with the smallest lattice energies appear at the bottom of the mass because of high power of solubility.

<h3>What is lattice energy? </h3>

The lattice energy is defined as the energy change upon the formation of one mole of crystalline ionic compound from its same constituent ions, that are assumed to be initially in the state of gases. It is also defined as measure of the cohesive forces which bind ionic solids together.

As the lattice energy of the ionic compound increase the solubility of that particular compound decrease. Hence compound which have low lattice energy are more soluble than compound having high lattice energy. When molten rocks cools and solidified, the compound having smallest lattice energy become more soluble than crystals of compound which have large lattice energy. Therefore, crystal of compound with the smallest lattice energy start appearing at the bottom of the mass.

Thus, we concluded that due to high solubility power of compound with low lattice energy appear at the bottom of the mass.

learn more about lattice energy:

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Many different localities are thought to be hotspots, found overlying mantle plumes, although scientists cannot agree on a defin
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(If this is correct, can I have Brainlist?)

Answer:

D) anomalous volcanoes such as those in Hawaii

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A fossilized animal that was killed by a volcanic eruption has 6.25 percent of its original amount of carbon-14 remaining; this
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You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution when ex
mojhsa [17]

Answer:

a. 1.78x10⁻³ = Ka

2.75 = pKa

b. It is irrelevant.

Explanation:

a. The neutralization of a weak acid, HA, with a base can help to find Ka of the acid.

Equilibrium is:

HA ⇄ H⁺ + A⁻

And Ka is defined as:

Ka = [H⁺] [A⁻] / [HA]

The HA reacts with the base, XOH, thus:

HA + XOH → H₂O + A⁻ + X⁺

As you require 26.0mL of the base to consume all HA, if you add 13mL, the moles of HA will be the half of the initial moles and, the other half, will be A⁻

That means:

[HA] = [A⁻]

It is possible to obtain pKa from H-H equation (Equation used to find pH of a buffer), thus:

pH = pKa + log₁₀ [A⁻] / [HA]

Replacing:

2.75 = pKa + log₁₀ [A⁻] / [HA]

As [HA] = [A⁻]

2.75 = pKa + log₁₀ 1

<h3>2.75 = pKa</h3>

Knowing pKa = -log Ka

2.75 = -log Ka

10^-2.75 = Ka

<h3>1.78x10⁻³ = Ka</h3>

b. As you can see, the initial concentration of the acid was not necessary. The only thing you must know is that in the half of the titration, [HA] = [A⁻]. Thus, the initial concentration of the acid doesn't affect the initial calculation.

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Answer:

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