Answer:
P = 5.868 atm
Explanation:
- Pt = (PN2O)(XN2O) + (PO2)(XO2)
assume T = 25°C = 298.15 K
∴ PN2O = 1 atm
∴ XN2O = nN2O/nt
∴ n = PV/RT....ideal gas
⇒ nN2O = ((1atm)(1L))/((0.082atm.L/K.mol)(298.15K)) = 0.041 mol N2O
∴ PO2 = 6 atm
∴ XO2 = nO2/nt
∴ nO2 = ((6atm)(6L))/((0.082atm.L/K.mol)(298.15K)) = 1.472 mol O2
⇒ nt = nN2O + nO2 = 0.041 + 1.472 = 1.513 mol
⇒ XN2O = 0.041/1.513 = 0.03
⇒ XO2 = 1.472/1.513 = 0.973
⇒ Pt = ((1atm)(0.03)) + ((6atm)(0.973))
⇒ Pt = 5.868 atm
Answer:
The answer to your question is: Cp = 0.129 J/g°C
Explanation:
Data
mass = 955 g of tungsten
T1 = 18°C
T2 = 100°C
Q = 10180 Joules
Cp = ?
Formula
Q = mCpΔT
Clear Cp from the equation
Cp = Q / mΔT
Substitution
Cp = 10180 / (955(100-18))
Cp = 10180 / (955(82))
Cp = 10180 / 78310
Cp = 0.129 J/g°C
Answer:
2.01 moles of P → 1.21×10²⁴ atoms
2.01 moles of N → 1.21×10²⁴ atoms
4.02 moles of Br → 2.42×10²⁴ atoms
Explanation:
We begin from this relation:
1 mol of PNBr₂ has 1 mol of P, 1 mol of N and 2 moles of Br
Then 2.01 moles of PNBr₂ will have:
2.01 moles of P
2.01 moles of N
4.02 moles of Br
To determine the number of atoms, we use the relation:
1 mol has NA (6.02×10²³) atoms
Then: 2.01 moles of P will have (2.01 . NA) = 1.21×10²⁴ atoms
2.01 moles of N (2.01 . NA) = 1.21×10²⁴ atoms
4.02 moles of Br (4.02 . NA) = 2.42×10²⁴ atoms
Answer:
The correct answer would be the third choice.
Homo-genesis mixtures are the same in composure, and will be hard to break apart other then with chemical means.
Hope this helps!