Answer:
R2 = 10.31Ω
Explanation:
For two resistors in parallel you have that the equivalent resistance is:
(1)
R1 = 13 Ω
R2 = ?
The equivalent resistance of the circuit can also be calculated by using the Ohm's law:
(2)
V: emf source voltage = 23 V
I: current = 4 A
You calculate the Req by using the equation (2):
Now, you can calculate the unknown resistor R2 by using the equation (1):
hence, the resistance of the unknown resistor is 10.31Ω
You would have to place your sensor above earth's atmosphere because it blocks out nearly all x-rays. this is why we have the Chandra observatory
hope this helps
Answer:
Approximately 
.
Explanation:
The formula for the kinetic energy 
of an object is:
,
where
is the mass of that object, and
is the speed of that object.
Important: Joule (
) is the standard unit for energy. The formula for requires two inputs: mass and speed. The standard unit of mass is 
while the standard unit for speed is 
. If both inputs are in standard units, then the output (kinetic energy) will also be in the standard unit (that is: joules,
Convert the unit of the arrow's mass to standard unit:
.
Initial of this arrow:
.
That's the same as the energy output of this bow. Hence, the efficiency of energy transfer will be:
.
as it is given that
now we will have
now the magnitude of this vector is given as
now to find the direction we can use
The hall voltage will be calculated using the formula:
E = Blv
where:
>Hall voltage: E = ?
>Magnetic field:
B = 0.200 Tesla or Wb/m^2
>Width of conductor or Diameter of Aorta:
l = 2.60 cm, converting to meter = .0260 m
>Velocity of charge flowing:
v = 60 cm/s, converting to meter = 0.6 m/s
Substituting the given :
E = (0.200 Wb/m^2) * (0.260 m) * (0.6 m/s)
E = (0.200 Wb/m^2) * (0.156 m^2/s)
E = 0.0312 Wb/s
Since 1 volt = 1 Wb/s then,
E = 0.0312 V or 31.2 mV
