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Assoli18 [71]
3 years ago
7

Ms. Terry Novel is driving down the highway at 26 m/s when the driver sees the light ahead turn yellow. It takes the driver 0.3

s to react and the maximum braking acceleration of her car is 5.3 m/s2. If the light stays yellow for a total of 4 seconds, how far does she travel in this time?
Physics
1 answer:
Ket [755]3 years ago
7 0

Answer:

67.8 m.

Explanation:

For 0.3 sec which is the response time , he will keep on moving with velocity

undiminished or at 26 m/s .

Distance travelled during this period

= 26 x .3 =7.8 m

For rest of the time ie during 4 - .3 = 3.7 s , he decelerates with deceleration of 5.3 ms⁻²  and initial velocity of 26 m/s

s = u t - 1/2 a t²

s = 26 x 3.7 - .5 x 5.3 x 3.7 x 3.7

= 96.2 - 36.28

= 60 m approx.

Total distance travelled

=60 + 7.8 = 67.8 m.

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Two point charges are brought closer together, increasing the force between them by a factor of 17. By what factor was their sep
nignag [31]

Answer:

\dfrac{r_1}{r_2}=4.123

Explanation:

Given:

Final force between them=17(initial force between them)

initial separation between them r_1

Final separation between them r_2

Let Q and q be the charges on them then

F_2=17F_1\\\dfrac{kQq}{r_2^2}=17\dfrac{kQq}{r_1^2}\\\dfrac{r_1^2}{r_2^2}=17\\\dfrac{r_1}{r_2}=4.123

6 0
3 years ago
A sled of mass 15 kg slides across the ground with a friction force of 80.85 N. What is k between the sled and the ground?
Dvinal [7]
The expression for the frictional force between the sled and the ground is:
F=k m g
where k is the coefficient of friction, m is the mass of the object and g=9.81 m/s^2 is the gravitational acceleration.

The friction force in our problem is F=80.85 N. The mass of the object is m=15 kg. Re-arranging the formula, we can find the value of k:
k= \frac{F}{mg}= \frac{80.85 N}{(15 kg)(9.81 m/s^2)}=0.55
8 0
4 years ago
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How does the input distance of a single fixed pulley compare to the out- put distance?
ololo11 [35]

A pulley is another sort of basic machine in the lever family. We may have utilized a pulley to lift things, for example, a banner on a flagpole.

<u>Explanation:</u>

The point in a fixed pulley resembles the support of a lever. The remainder of the pulley behaves like the fixed arm of a first-class lever, since it rotates around a point. The distance from the fulcrum is the equivalent on the two sides of a fixed pulley. A fixed pulley has a mechanical advantage of one. Hence, a fixed pulley doesn't increase the force.

It essentially alters the direction of the force. A moveable pulley or a mix of pulleys can deliver a mechanical advantage of more than one. Moveable pulleys are appended to the item being moved. Fixed and moveable pulleys can be consolidated into a solitary unit to create a greater mechanical advantage.

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Imagine a landing craft approaching the surface of Callisto, one of Jupiter's moons. If the engine provides an upward force (thr
nordsb [41]

Answer:

W=3456 N

Explanation:

Force 1 F_1=3456

Force 2 F_2=2333N

Acceleration at stage 2 a_2=0.39

Generally the weight of the Craft W is given as

W= upward force(thrust)

Therefore

W=3456 N

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What would happen to a 100N gravitational force if both masses were doubled and the radius were
grin007 [14]

Answer:

They are the only joints that can do 360 degrees and rotate with their own axis. But, because of its free-moving, it is prone to any dislocation compared to other movable joints.

Explanation:

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