Question

Calculate the root mean square velocity of nitrogen molecules at 25 C.

Answer 1

 root mean square= square root of ( 3RT/M) 

 R = 8.314 J/K/mole 
T = 25 + 273 = 298 K 
M = molecular mas of N2 in kg = 28 X 10^-3 kg 

put values... 

 root mean square = square root of ( 3 X 8.314 X 298/28 X 10^-3)
= square root of ( 265454.143)
= 515.2 m/s
so option A is right
hope this helps