Answer:

Explanation:
We are given that
Surface area of membrane=
Thickness of membrane=
Assume that membrane behave like a parallel plate capacitor.
Dielectric constant=5.9
Potential difference between surfaces=85.9 mV
We have to find the charge resides on the outer surface of membrane.
Capacitance between parallel plate capacitor is given by

Substitute the values then we get
Capacitance between parallel plate capacitor=

V=


Hence, the charge resides on the outer surface=
BaCI2 stands for Barium Chloride.
The answer would be erin out of all of them thank me later :)
Answer:
The distance is 
Explanation:
From the question we are told that
The wavelength of the light is 
The distance between the slit is 
The between the first and second dark fringes is 
Generally fringe width is mathematically represented as

Where D is the distance of the slit to the screen
Hence

substituting values


Answer:
Distance will be 49.34 m
Explanation:
We have given wavelength 
Diameter of the antenna d = 2.7 m
Range L = 7.8 km = 7800 m
We have to find the smallest distance hat two speedboats can be from each other and still be resolved as two separate objects D
We know that distance is given by 
So distance D will be 49.34 m