An object is thrown vertically upward with an initial velocity of 50 m/s. Find

A heliocentric system is _____-centered.

aniked [119]

A heliocentric system is a sun-centered

3 0

4 years ago

Read 2 more answers

Why are clouds considered to be a part of the hydrosphere?

blondinia [14]

It is considered parts of the Hydrosphere because water condenses in clouds and falls as precipitation so it is a vital part of the hydrosphere.

7 0

4 years ago

use the general formulas for gravitational force and centripetal force to derive the relationship between speed and orbital radi

MrRissso [65]

Answer:

$v = \sqrt{\frac{GM}{r}}$

Explanation:

The universal law of gravitation is defined as:

$F = G\frac{Mm}{r^{2}}$ (1)

Where G is the gravitational constant, M and m are the masses of the two objects and r is the distance between them.

The centripetal force can be found by means of Newton's second law:

$F = ma$ (2)

Since it is a circular motion, the acceleration can be defined as:

$a = \frac{v^{2}}{r}$ (3)

Where v is the velocity and r is the orbital radius.

Replacing equation (3) in equation (2) it is gotten:

$F = m\frac{v^{2}}{r}$ (4)

Hence,

$m\frac{v^{2}}{r} = G\frac{Mm}{r^{2}}$

Then, v can be isolated:

$mv^{2} = G\frac{Mmr}{r^{2}}$

$mv^{2} = G\frac{Mm}{r}$

$v^{2} = G\frac{Mm}{mr}$

$v^{2} = \frac{GM}{r}$

$v = \sqrt{\frac{GM}{r}}$

So the relationship between speed and orbital radius is given by the expression $v = \sqrt{\frac{GM}{r}}$

8 0

3 years ago

A water-skier is moving at a speed of 14.3 m/s. When she skis in the same direction as a traveling wave, she springs upward ever

kiruha [24]

Answer:

a) 1.95 m/s

b) 5.56 m

Explanation:

Given that:

Velocity of the skier $(V_s)$ = 14.3 m/s

For the skier moving in the direction of the wave, we have:

Period (T) = 0.450 s

Relative velocity (V) of the skier in regard with the wave = $(V_s - V_w)$

where:

$V_s$ = velocity of the skier

$V_w$ = velocity of the wave

The wavelength $(\lambda)$ can be written as:

$\lambda = (V_s-V_w)T$

$\lambda = (V_s-V_w) 0.450m$ ---------------> Equation (1)

For the skier moving opposite in the direction of the wave, we have:

Period (T) = 0.342 s

Relative velocity (V) of the skier in regard with the wave = $(V_s + V_w)$

The wavelength $(\lambda)$ can be written as:

$\lambda = (V_s+V_w)T$

$\lambda = (V_s+V_w) 0.342m$ ------------------> Equation 2

Equating equation (1) and equation (2) and substituting $V_s$ = 14.3 m/s ; we have:

$(V_s-V_w) 0.450m = (V_s-V_w) 0.342m$

$0.450m(V_s)-0.450m(V_w) = 0.342m(V_s)+0.342m(V_w)$

Collecting the like terms; we have:

$0.450m(V_s) - 0.342m(V_s) = 0.342m(V_w)+0.450m(V_w)$

$(V_s)(0.450m - 0.342m) = (V_w)0.342m+0.450m$

$14.3m/s(0.450m - 0.342m) = (V_w)0.342m+0.450m$

$14.3m/s(0.108m = (V_w)0.792m$

$1.5444m^2/s = (V_w)0.792m$

$(V_w) = \frac{1.5444m^2/s}{ 0.792m}$

$(V_w) = 1.95 m/s$

b)

The Wavelength of the wave can be calculated using : $( \lambda }) = (V_s-V_w) 0.450m$

$({\lambda}) = (14.3 m/s -1.95 m/s)(0.450)$

$(\lambda) = (12.35)0.450m$

$(\lambda)= 5.5575 m$

λ ≅ 5.56 m

5 0

3 years ago

Consider a car that travels between points A and B. The car's average speed can be greater than the magnitude of its average vel

ryzh [129]

Answer: A.True

Explanation: simply put the magnitude of the speed is a function of Distance while the magnitude of velocity is a function of Displacement. Displacement is the average Distance moved in different directions which will be smaller in magnitude compared to the Total Distance used the calculating the magnitude of speed.

4 0

4 years ago