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3 years ago

10

A 3.0 kg pendulum swings from point A of height ya = 0.04 m to point B of height yb = 0.12 m, as seen in the diagram below.

2 answers:

lakkis [162]3 years ago

5 0

i dont know soory pls give brainlyist

juin [17]3 years ago

4 0

Answer:

3.0−0.12=2.88 or 2.88÷0.04=72

0.04×3.0=0.12 and 0.04+3.0=3.04

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The temperature scale used in science is the _______ scale.

vivado [14]

The temperature scale used in science is the Kelvin scale. The correct option among all the options given in the question is option "a". This is the standard scale used for measuring in astronomical and thermodynamics fields. The other scales can create complications as different countries use different type of scales.

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4 years ago

Why are planets closer to the sun made of different substance than planets father from the sun?

MA_775_DIABLO [31]

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4 years ago

Two identical objects (A, B) travel circles of the same radius, but object A completes three times as many rotations as object B

malfutka [58]

Answer:

a) One-ninth the force acting on object A.

Explanation:

First, we derive an expression for the centripetal force acting on both objects.

For object A, centripetal force is:

$F_A = \frac{m{v_A}^2}{r}$

For object B, centripetal force is:

$F_B = \frac{m{v_B}^2}{r}$

We are given that they have the same mass and they move in circles of the same radius.

If object A completes three times as many rotations as object B, then, object must have 3 times the speed of object B.

Hence:

${v_A} = 3*{v_B}$

Therefore, $F_A$ becomes:

$F_A = \frac{m({3*v_B}^{2} )}{r}\\\\\\F_A = \frac{9m{v_B}^{2}}{r}$

$F_A = 9F_B$

=> $F_B = \frac{1}{9} F_A$

Therefore, the net centripetal force acting on object B is one-ninth of the force acting on object A.

4 0

3 years ago

Andrei [34K]

Answer:

C

Explanation:

because warm air is less dense, and warm air rises and cold air sinks. (did research) hope this helps!! :)

4 0

4 years ago

Read 2 more answers

Two train whistles, and , each have a frequency of 392 Hz. is stationary and is moving toward the right (away from ) at a speed

trasher [3.6K]

Answer:

Part a)

f = 371.1 Hz

Part b)

f = 417.7 Hz

Part c)

beat frequency = 46.6 Hz

Explanation:

Part a)

Due to doppler's Effect the frequency of the sound heard by the train which is moving away from the observer is given as

$f_1 = f_0\frac{v + v_o}{v + v_s}$

$f_1 = 392(\frac{340 + 15}{340 + 35})$

$f_1 = 371.1 Hz$

Part b)

Now from the second train which is approaching the person we can say

$f_2 = f_0\frac{v - v_o}{v - v_s}$

$f_2 = 392(\frac{340 - 15}{340 - 35})$

$f_2 = 417.7 Hz$

Part c)

As we know that beat frequency is the difference in the frequency from two sources

$f_b = f_2 - f_1$

$f_b = 417.7 - 371.1 = 46.6 Hz$

8 0

3 years ago